Question

我是django的新手，对django MVT概念了解甚少，

我的问题是关于Django应用程序的，我遇到了这个愚蠢的错误，但是我不知道怎么回事，我一次又一次地检查了代码中的所有内容，并且一切正常，但是我不知道怎么不起作用。 / p>

Page not found (404)

我的项目名称：融合
我的应用名称：django_adminlte
python 3.7
django 2.0
MySql

我的错误：

 Page not found (404)
 Request Method:    POST
 Request URL:   http://127.0.0.1:8000/emp

 Using the URLconf defined in fusion.urls, Django tried these URL patterns, in this order:

admin/
[name='login']
home/ [name='home']
signup/ [name='signup']
employee/ [name='emp']
show/ [name='show']
edit/<int:id>
update/<int:id>
delete/<int:id>
accounts/

The current path, emp, didn't match any of these.

emp方法不会重定向到显示方法

views.py

from django.shortcuts import render,redirect
from django.contrib.auth.forms import UserCreationForm,AuthenticationForm
from django.contrib.auth.decorators import login_required
from django.contrib.auth.models import User
from django_adminlte.forms import EmployeeForm
from django_adminlte.models import Employee

def emp(request):
if request.method == "POST":
    form = EmployeeForm (request.POST) # here "form" is one varible
    if form.is_valid():
        try:
            form.save()
            return redirect("/show")
        except:
            pass
else:
    form = EmployeeForm()
return render(request,"employee/employee_index.html",{'form':form})

def show(request):
employees = Employee.objects.all()
return render(request,"employee/show.html",{'employees': employees})

urls.py

from django.conf.urls import url
from django.contrib import admin
from django.urls import path,include
from django_adminlte import views

urlpatterns = [
path('admin/', admin.site.urls),

path('',views.login,name='login'),
path('home/',views.home,name='home'),
path('signup/',views.signup,name='signup'),

path('employee/',views.emp,name='emp'),
path('show/',views.show,name='show'),
path('edit/<int:id>',views.edit),
path('update/<int:id>',views.update),
path('delete/<int:id>',views.delete),

path('accounts/',include('django.contrib.auth.urls')),
]

HTML

{% extends 'adminlte/base.html' %}

{% block content %}

<!-- Horizontal Form -->
<form method="POST" class="post-form" action="/emp">
    {% csrf_token %}

<div class="container">
    <br>
    <div class="form-group row">
    <label class="col-sm-1 col-form-lable"></label> 
        <div class="col-sm-4">
            <h3>Enter Details</h3>
        </div>
    </div>
    <div class="form-group row">
        <label class="col-sm-2 col-form-lable">Employee ID : </label>
        <div class="col-sm-4">
            {{ form.eid }}
        </div>
    </div>
    <div class="form-group row">
        <label class="col-sm-2 col-form-lable">Employee Name : </label>
        <div class="col-sm-4">
            {{ form.ename }}
        </div>
    </div>
    <div class="form-group row">
        <label class="col-sm-2 col-form-lable">Employee Email : </label>
        <div class="col-sm-4">
            {{ form.eemail }}
        </div>
    </div>
    <div class="form-group row">
        <label class="col-sm-2 col-form-lable">Employee Contact :</label>
        <div class="col-sm-4">
            {{ form.econtact }}
        </div>
    </div>
    <button type="submit" class="btn btn-primary">Submit</button>
</div>

谢谢！

Answer 1

尝试将网址格式更改为以下内容：

url(r'^emp/', 'django_adminlte.views.emp', name = 'emp')

Answer 2

您可以将模板中的url标记与路径引用名称一起使用。您可以从here

检查

在您的示例中，您为“ employee /”路径定义了引用名称“ emp”，因此您可以同时使用<form method="POST" class="post-form" action="{% url 'emp' %}">和<form method="POST" class="post-form" action="/employee/">。

Answer 3

def emp(request):
try:
    if request.method == "POST":
        form = EmployeeForm (request.POST) # here "form" is one varible
        if form.is_valid():
            try:
                form.save()
                return redirect("/show")
            except:
                pass
    else:
        form = EmployeeForm()
    return render(request,"employee/employee_index.html",{'form':form})
except TemplateNotFound as e:
    return render('404.html')

如何修复Django 2.0中的Page not found（404）错误？

3 个答案: