我正在尝试进行比较，以查看相同的客户是否在不同销售数据库的2个表中。在大多数情况下，如果正确输入或不为空，则两个表中都有一个匹配的帐号。
如果没有匹配的帐号，我需要查看相似的地址。
现在我正在使用CTE，但是当没有帐号匹配时，我没有得到正确的结果来按地址相似性进行匹配。
使用临时表会更好，如果可以，怎么办？
这是我的代码：
-第一个cte提取所有非空帐户并重新格式化帐户号以匹配第二个表中帐户的格式
WITH Table1_Reformat_AccountNum_CTE
AS
(
Select
t1.account_number
,t1.account_name
,t1.address_1
,t1.address_2
,t1.city
,t1.state
,t1.zip
,CASE
WHEN t1.account_number LIKE '%xyz-%' THEN LTRIM(RTRIM(RIGHT(t1.account_number, LEN(t1.account_number)-9)))
WHEN t1.account_number LIKE 'qrs:% -lmo' THEN REPLACE(LTRIM(RTRIM(RIGHT(t1.account_number, LEN(t1.account_number)-5))), '-lmo', '')
ELSE REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE( REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(RIGHT(t1.account_number, LEN(t1.account_number)-5), '-', ''), ' ', ''), '.', ''), ',', ''), 'out', ''), '#', ''), '0ut', ''), '''', ''), '_', ''), '*', ''),'<',''),'>',''),'^','')
END AS account_num_formatted
From [database_1].[dbo].[sales_table_1] t1
WHERE t1.account_number IS NOT NULL
)
-- 2nd cte matched reformatted account numbers to account numbers in table 2
,Table2_AccountNum_Matches_CTE
AS
(
SELECT
t1.account_num_formatted
,t2.account_number
,t2.account_name
,t2.address_1
,t2.address_2
,t2.city
,t2.state
,t2.zip
FROM Table1_Reformat_AccountNum_CTE ref
INNER JOIN [database_2].[dbo].[sales_table_2] t2
ON t2.account_number = t1.account_num_formatted
)
-- 3rd cte finds all left over accounts in table 1 that have no match in table 2
,Table1_Non_Matches_Cte
AS
(
SELECT
t1.account_num_formatted
,t1.account_name
,t1.address_1
,t1.address_2
,t1.city
,t1.state
,t1.zip
FROM Table1_Reformat_AccountNum_CTE ref
WHERE t1.account_num_formatted NOT IN (SELECT acm.account_num_formatted FROM Table2_AccountNum_Matches_CTE acm)
)
-- 3rd cte finds all left over accounts in table 2 that have no match in table 1
,Table2_Non_Matches_Cte
AS
(
SELECT
t2.account_number
,t2.account_name
,t2.address_1
,t2.address_2
,t2.city
,t2.state
,t2.zip
FROM [database_2].[dbo].[sales_table_2] t2
WHERE t2.account_number NOT IN (SELECT acm.account_num_formatted FROM Table2_AccountNum_Matches_CTE acm)
)
-- attemtps to find all accounts in table 2 that have no match in account number in table 1 but match on address
SELECT
t1.account_num_formatted
,t1.account_name
,t1.address_1
,t1.address_2
,t1.city
,t1.state
,t1.zip
,t2.account_number
,t2.account_name
,t2.address_1
,t2.address_2
,t2.city
,t2.state
,t2.zip
FROM Table1_Reformat_AccountNum_CTE ref
FULL OUTER JOIN [database_2].[dbo].[sales_table_2] t2
ON t1.account_num_formatted = t2.account_number
WHERE t2.account_number IN (SELECT non.account_number FROM Table2_Non_Matches_Cte non )
AND t1.address_1 LIKE '%'+ t2.address_1 +'%'
AND t1.city LIKE '%'+ t2.city+'%'
AND t2.state LIKE '%'+ t2.state+'%'
AND t2.zip = '%'+t2.zip+'%'
样本数据：
表1
——————
Acc | Name | Add 1| Add 2 | City | State | Zip
————————————————————-
1 store1 113 st lane mulberry tx 12344
Null store2 114 st lane mulberry tx 34254
6 store3 113 st lane mulberry tx 98764
7 store4 115 st lane mulberry tx 74631
8.1 store5 116 st lane mulberry tx 12347
表2
——————
Acc | Name | Add 1| Add 2 | City | State | Zip
————————————————————-
1 store1 113 st lane mulberry tx 12344
Null store2 114 st lane mulberry tx 34254
9 store8 213 ha ave juniper ct 46738
5 store9 217 wa ave juniper ct 98376
8 store5 116 st lane mulberry tx 12347
预期结果：
Acc | Name | Add 1| Add 2 | City | State | Zip
————————————————————-
1 store1 113 st lane mulberry tx 12344
Null store2 114 st lane mulberry tx 34254
8 store5 116 st lane mulberry tx 12347