错误：必须提供符号或字符串作为参数

Question

我有一些R-markdown代码，这些代码过去可以在笔记本电脑上正常工作。现在，当我尝试将它们编织到HTML文件时，出现此错误：

Error: Must supply a symbol or a string as argument.

有趣的是，我的同事说代码在她的台式计算机上可以正常工作。她正在使用窗户。

在以下代码行之后出现此错误（另请参见屏幕截图）：

acs <-
structure(list(`County Name` = c("U.S.", "Ohio", "Adams", "Allen", 
"Ashland", "Ashtabula"), Year = c(2000, 2000, 2000, 2000, 2000, 
2000), Sex = c("Male", "Male", "Male", "Male", "Male", "Male"
), `Age Group` = c("All", "All", "All", "All", "All", "All"), 
    `6th Grade or Less` = c(0.824, 0.038, 0.061, 0.012, 0.04, 
    0.031), `7th- 12th (No Diploma)` = c(0.085, 0.275, 0.343, 
    0.28, 0.283, 0.286), `High School Graduate` = c(0.037, 0.341, 
    0.347, 0.442, 0.436, 0.44), `Some College` = c(0.054, 0.171, 
    0.162, 0.149, 0.119, 0.148), `Bachelor's Degree` = c(NA, 
    0.097, 0.038, 0.067, 0.066, 0.053), `Graduate Degree` = c(NA, 
    0.077, 0.05, 0.049, 0.056, 0.041), `White Non-Hispanic` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Black Non-Hispanic` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Other Races Non-Hispanic in` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), Hispanic = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Total 60+` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Median Age for 60+` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Population Age 60 & Older` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Population` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Population Living Alone` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Grand Parents Living with Grand Children` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Population with High School Diploma or Higher Degree` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% of Population with College Degree` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Median Income` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% below 100% of Federal Povery Treshhold income` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% Medicaid Eligible` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `% employed` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Living Alone` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `0-100%` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `101-200%` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `201-300%` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `301-400%` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `>400%` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), Married = c(0.529, 
    0.752, 0.732, 0.774, 0.813, 0.724), `Widowed/Divorced/Separated` = c(0.168, 
    0.207, 0.22, 0.195, 0.153, 0.223), `Never Married` = c(0.303, 
    0.041, 0.047, 0.031, 0.034, 0.053), `At or Below Poverty  Treshhold` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Above Four Times Poverty  Treshhold` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Income to poverty_less 1` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Income to poverty_less 1-1.99` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Income to poverty_less 2-2.99` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Income to poverty_less 3-3.99` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_), `Income to poverty_less 4+` = c(NA_real_, 
    NA_real_, NA_real_, NA_real_, NA_real_, NA_real_)), row.names = c(NA, 
-6L), class = c("tbl_df", "tbl", "data.frame"))

edu.county<-acs %>% 
  filter(Sex == "Total", `Age Group`=="All", `County Name`%in% c(county, "Ohio"), Year == max(acs$Year))

edu.county$`County Name`<-factor(edu.county$`County Name`, levels = c("Ohio", county))

edu.county<-edu.county %>% 
  select(`6th Grade or Less`, `7th- 12th (No Diploma)`, `High School Graduate`, 
         `Some College`, `Bachelor's Degree`, `Graduate Degree`)  %>% 
  gather(c(`6th Grade or Less`, `7th- 12th (No Diploma)`, `High School Graduate`, 
           `Some College`, `Bachelor's Degree`, `Graduate Degree`), EduPerc) 
County<-rep(c("Ohio", county), 6)
edu.county<-cbind(edu.county, County) 

Answer 1

我认为犯罪者分为以下两行：

gather(c(`6th Grade or Less`, `7th- 12th (No Diploma)`, `High School Graduate`, 
           `Some College`, `Bachelor's Degree`, `Graduate Degree`), EduPerc) 

gather需要键和值列名称，以字符串形式给出。您正在为其提供名称的向量（c(…)）。这是行不通的，目前尚不清楚您打算在这里做什么。您可能需要以下内容：

… gather(`Education level`, EduPerc) …

Answer 2

正如我在问题中提到的那样，代码可以在同事的台式计算机上正常工作。她正在使用R 3.4.3，而我正在使用3.5。版。我从笔记本电脑（不是R Studio）中删除了R，并安装了稍旧的笔记本电脑（R版本3.3.3（2017-03-06）-“另一个独木舟”）。这解决了问题；我不再收到“错误：必须提供符号或字符串作为参数”的错误消息。 感谢大家的意见和建议。