我正在尝试从PokeAPI获取演化链，并且在stackoverflow How to get pokemon's evolution chain
中得到了另一个答案顺便说一句，我不了解如何从“ evolves_to数组”中获取所有元素，然后返回更高级别以转到数组本身的下一个元素。例如，我想要一个像这样的数组：
[{
"species_name": "charmander",
"min_level": 1,
"trigger_name": null,
"item": null
}, {
"species_name": "charmeleon",
"min_level": 16,
"trigger_name": "level-up",
"item": null
}, {
"species_name": "charizard",
"min_level": 36,
"trigger_name": "level-up",
"item": null
}]
但是从这样的JSON中，带有带有多个元素的“ evolves_to”数组：
{
"baby_trigger_item": null,
"chain": {
"evolution_details": [],
"evolves_to": [
{
"evolution_details": [
{
"gender": null,
"held_item": null,
"item": null,
"known_move": null,
"known_move_type": null,
"location": null,
"min_affection": null,
"min_beauty": null,
"min_happiness": null,
"min_level": 7,
"needs_overworld_rain": false,
"party_species": null,
"party_type": null,
"relative_physical_stats": null,
"time_of_day": "",
"trade_species": null,
"trigger": {
"name": "level-up",
"url": "https://pokeapi.co/api/v2/evolution-trigger/1/"
},
"turn_upside_down": false
}
],
"evolves_to": [
{
"evolution_details": [
{
"gender": null,
"held_item": null,
"item": null,
"known_move": null,
"known_move_type": null,
"location": null,
"min_affection": null,
"min_beauty": null,
"min_happiness": null,
"min_level": 10,
"needs_overworld_rain": false,
"party_species": null,
"party_type": null,
"relative_physical_stats": null,
"time_of_day": "",
"trade_species": null,
"trigger": {
"name": "level-up",
"url": "https://pokeapi.co/api/v2/evolution-trigger/1/"
},
"turn_upside_down": false
}
],
"evolves_to": [],
"is_baby": false,
"species": {
"name": "beautifly",
"url": "https://pokeapi.co/api/v2/pokemon-species/267/"
}
},
{
"evolution_details": [
{
"gender": null,
"held_item": null,
"item": null,
"known_move": null,
"known_move_type": null,
"location": null,
"min_affection": null,
"min_beauty": null,
"min_happiness": null,
"min_level": 7,
"needs_overworld_rain": false,
"party_species": null,
"party_type": null,
"relative_physical_stats": null,
"time_of_day": "",
"trade_species": null,
"trigger": {
"name": "level-up",
"url": "https://pokeapi.co/api/v2/evolution-trigger/1/"
},
"turn_upside_down": false
}
],
"evolves_to": [
{
"evolution_details": [
{
"gender": null,
"held_item": null,
"item": null,
"known_move": null,
"known_move_type": null,
"location": null,
"min_affection": null,
"min_beauty": null,
"min_happiness": null,
"min_level": 10,
"needs_overworld_rain": false,
"party_species": null,
"party_type": null,
"relative_physical_stats": null,
"time_of_day": "",
"trade_species": null,
"trigger": {
"name": "level-up",
"url": "https://pokeapi.co/api/v2/evolution-trigger/1/"
},
"turn_upside_down": false
}
],
"evolves_to": [],
"is_baby": false,
"species": {
"name": "dustox",
"url": "https://pokeapi.co/api/v2/pokemon-species/269/"
}
}
],
"is_baby": false,
"species": {
"name": "cascoon",
"url": "https://pokeapi.co/api/v2/pokemon-species/268/"
}
}
],
"is_baby": false,
"species": {
"name": "silcoon",
"url": "https://pokeapi.co/api/v2/pokemon-species/266/"
}
}
],
"is_baby": false,
"species": {
"name": "wurmple",
"url": "https://pokeapi.co/api/v2/pokemon-species/265/"
}
},
"id": 135
}
所以，我该如何将其弄平？感谢谁回答我，并对我的英语不好对不起。
答案 0 :(得分：0)
我知道为时已晚，但对于进一步的提问者，我在 C# 中创建了这个算法，您可以引入进化链并返回所有子链：
public static void PrintEvolutionChain(EvolutionChain pokemon)
{
int counter = 1;
List<List<Pokemon>> pokemons = new List<List<Pokemon>>();
List<Pokemon> pokemonsTemp = new List<Pokemon>();
foreach (EvolvesTo envolveTo in pokemon.envolvesTo)
{
pokemonsTemp.Add(pokemon.Pokemon);
PrintPreorder(envolveTo,pokemons,pokemonsTemp);
}
foreach (List<Pokemon> pokemones in pokemons)
{
Console.WriteLine($"Chain: {counter}");
foreach (Pokemon pokemonchain in pokemones)
{
Console.WriteLine($"Pokemon: {pokemonchain.Name}");
}
counter++;
}
}
public static void PrintPreorder(EvolvesTo pokemon, List<List<Pokemon>> pokemons, List<Pokemon> pokemonsTemp)
{
pokemonsTemp.Add(pokemon.pokemon);
if (pokemon == null || pokemon.envolvesTo.Count == 0 )
{
pokemons.Add(new List<Pokemon>(pokemonsTemp));
pokemonsTemp.Clear();
return;
}
if(pokemon.envolvesTo.Count == 1)
{
foreach (EvolvesTo envolveTo in pokemon.envolvesTo)
{
PrintPreorder(envolveTo, pokemons, pokemonsTemp);
}
}
else if (pokemon.envolvesTo.Count > 1){
List<Pokemon> pokemonsTempTemp = new List<Pokemon>(pokemonsTemp);
foreach (EvolvesTo envolveTo in pokemon.envolvesTo)
{
if (pokemonsTemp.Count == 0)
pokemonsTemp = pokemonsTempTemp;
PrintPreorder(envolveTo, pokemons, pokemonsTemp);
}
}
}
它可以更干净，但目前它有效，如果您知道如何清洁它，请在下方评论