Question

我想通过Pod Alamofire（SessionManager）将照片从图库（iOS）上传到服务器（通过代码中的.getWalluploadUrl获取的uploadUrl是正确的）我正在尝试使用imagePicker选择一张照片。但是接下来在Alamofire上传中会出错：

multipartEncodingFailed（原因：Alamofire.AFError.MultipartEncodingFailureReason.bodyPartFileNotReachableWithError（atURL：file：///var/mobile/Containers/Data/Application/366A5FD0-D597-44DC-A6C7-943DDEAB03B7/Documents/asset.JPG，错误：错误域= NSCocoaErrorDomain代码= 260“无法打开文件“ asset.JPG”，因为没有这样的文件。” UserInfo = {NSURL = file：/// var / mobile / Containers / Data / Application / 366A5FD0- D597-44DC-A6C7-943DDEAB03B7 / Documents / asset.JPG，NSFilePath = / var / mobile / Containers / Data / Application / 366A5FD0-D597-44DC-A6C7-943DDEAB03B7 / Documents / asset.JPG，NSUnderlyingError = 0x28375c9f0 {Error Domain = NSPOSIXErrorDomain代码= 2“没有这样的文件或目录”}}））

为什么此文件不存在？用imagePicker在哪里得到错误的本地路径？

代码（我知道这段代码很糟糕，但是我只是想找出本地路径的问题）：

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [UIImagePickerController.InfoKey : Any]) {
    let imageUrl          = info[UIImagePickerController.InfoKey.referenceURL] as! NSURL
    let imageName         = imageUrl.lastPathComponent
    let documentDirectory = NSSearchPathForDirectoriesInDomains(.documentDirectory, .userDomainMask, true).first!
    let photoURL          = NSURL(fileURLWithPath: documentDirectory)
    let localPath         = photoURL.appendingPathComponent(imageName!)
    let image             = info[UIImagePickerController.InfoKey.originalImage]as! UIImage
    let data              = image.pngData()

    self.getWalluploadUrl { (uploadUrl) in
        let sessionManager = SessionManager.default
        sessionManager.upload(
            multipartFormData: {
                data in
                data.append(
                    localPath!, //????? Incorrect path
                    withName: "file",
                    fileName: imageName!,
                    mimeType: "image/jpeg"
                )
        },
            to: uploadUrl,
            encodingCompletion: {
                (encodingResult) in
                switch encodingResult {
                case .success(let upload, _, _):
                    upload
                        .uploadProgress { (progress) in
                            print("progress:",progress)
                        }
                        .responseJSON { response in
                            switch response.result {
                            case .success(let value):
                                let json = JSON(value)
                                print(json)
                            case .failure(let error):
                                print(error)
                            }

                    }
                case .failure(let error):
                    print(error)
                }
        }
        )

    }

Answer 1

我找到了Swift 4.2的正确方法。它的工作原理：

#include <iostream>
#include <string>
using namespace std;

template <typename k>
class stack;


template <typename k>
class node{
    private:
        friend class stack<k>;
        k data;
        node<k> *next;
    public:
        node(k _x): data(_x), next(NULL) {}
};
template <typename k>
class stack{
    private:
        node<k> *start;
        unsigned int i;
    public:
        stack(): start(NULL), i(0) {}
        ~stack(){
            while(i!=0) pop();
        }
        void push(k element){
            node<k> *ptr;
            node<k> *temp;
            ptr=new node<k>(element);
            if(start==NULL){
                start=ptr;
                ptr->next==NULL;
            }
            else{
                while(temp->next!=NULL) temp=temp->next;
                temp->next=ptr;
                ptr->next=NULL; 
            }
            i++;
        }
        int pop(){
            if(i==1){
                int item=start->data;
                start=NULL;
                i=0;
                return item;
            }
            else{
            node<k> *temp=start;        //k is my typenam in templates
            node<k> *top=start;
            while(temp->next!=NULL) temp=temp->next;  //getting to last element
            while(top->next!=temp) top=top->next;   //getting to element before the last
            top->next=NULL;         //setting next to NULL
            int item=temp->data;    //getting data from element popped
            delete(temp);           //deleting last node
            i--;                    //decreasing the size
            return item;            //returning popped element
            }           
        }
        bool isempty(){
            if(i==0) return 1;
            else return 0;
        }
        int rozmiar(){
                return i;
        }
};



int main()
{
    stack<char> s;
    string slowo;
    cin>>slowo;
    for(int i=0; i<slowo.length(); i++){
        s.push(slowo[i]);
    }
    for(int i=0; i<slowo.length(); i++){
        s.pop();
    }

    return 0;
}

它不需要使用 .path.lastPathComponent。。这已经是完整且正确的本地路径（作为URL）。

注意：所有照片的URL（以及其他文件的URL）都是临时的，下次您启动该应用程序时将有所不同。

如何从图片选择器中快速获取照片本地网址

1 个答案: