“给出n个数字的列表L,取绝对值的总和除以L中元素的数量。”我该怎么办?
这是我到目前为止所拥有的
start
Get values for list L and n
INDEX = 1
while (INDEX ≤ n) do
Read: n;
Set sum = 0;
for i = 1 to n by 1 do
Set sum = sum + i
答案 0 :(得分:0)
目前尚不清楚-n是否为先前的L已知
read n
read n values in L
sum = 0
for i = 1 to n by 1 do //assuming 1-based list indexing
sum = sum + Abs(L[i])
av = sum / n