将网址传递给dns.lookup（）

Question

我在dns.lookup（）上获取网址错误。有帮助吗？举例来说 https://stackoverflow.com/questions/41942690/removing-http-or-http-and-www/41942787

我已经删除了https：//，但仍然无法正常工作。

var dns = require('dns');
var url = "https://stackoverflow.com/questions/41942690/removing-http-or-http-and-www/41942787";
dns.lookup(url,(error,address,family)=>{
  console.log(error,address,family)
})

Answer 1

dns.lookup(hostname[, options], callback)

解析URL并检索主机名，然后将其传递给dns.lookup()函数。

const dns = require('dns');
const url = require('url'); 
const lookupUrl = "https://stackoverflow.com/questions/41942690/removing-http-or-http-and-www/41942787";

const parsedLookupUrl = url.parse(lookupUrl);

console.log(parsedLookupUrl);

  

网址身份验证：空哈希值：空主机：“ stackoverflow.com”主机名：   “ stackoverflow.com” href：   “ removing http:// or http:// and www”   路径：“ / questions / 41942690 / removing-http-or-http-and-www / 41942787”   路径名：“ / questions / 41942690 / removing-http-or-http-and-www / 41942787”   端口：null协议：“ https：”查询：null搜索：null斜杠：true   网址原型

dns.lookup(parsedLookupUrl.hostname,(error,address,family)=>{
  console.log(error,address,family)
});