热传递值会引发可运行的onSuccess响应吗?

时间:2019-01-20 23:35:21

标签: android kotlin retrofit runnable

所以我的目标就像标题所说的是将API响应结果传递给一个片段一个onSuccess.run()方法。只是为了提供一些上下文,我开始在Manager类中执行如下方法:

    override fun callUser(onSuccess:Runnable, onFailure:Runnable){

 NetworkManager.instance.performCall(NetworkManager.REGISTRATION.verifyUser(id),
                object : NetworkManager.OnRequestCallback<UserInfoResponse> {
                    override fun onSuccess(body: UserInfoResponse?) {
                        body?.data?.let {
                            onSuccess.run()
                        }
                    }

                    override fun onError(errorBody: String?) {
                        onFailure.run()
                    }
                })
    }

然后我转到一个片段,像上面这样调用上面的方法:

objectManager.callVerifyAdvisor(
                    Runnable {[On Success stuff },
                    Runnable {[On Error]}
        }

问题是,尽管我可以在片段中决定要在onSuccess()onFailure()方法中执行的操作,但我无法通过执行以下操作来将API Results赋予该片段这样。

所以我的想法是做类似[我用评论指定要关注的部分]之类的事情:

NetworkManager.instance.performCall(NetworkManager.REGISTRATION.verifyUser(id),
                    object : NetworkManager.OnRequestCallback<UserInfoResponse> {
                        override fun onSuccess(body: UserInfoResponse?) {
                            body?.data?.let {
                                it.userName // I get this from api response
                                onSuccess.run()
                            }
                        }

                        override fun onError(errorBody: String?) {
                            onFailure.run()
                        }
                    })
        }

然后在我的片段中,我想要这样的东西:

   objectManager.callVerifyAdvisor(
              Runnable {[On Success stuff }, //receive here the it.userName
              Runnable {[On Error]}
}

有人可以给我任何想法吗?旁注->我在标签上放了kotlin,因为它有某种功能。

1 个答案:

答案 0 :(得分:2)

您只需要将onSuccess从Runnable替换为您的自定义功能类型回调:

override fun callUser(onSuccess: (String) -> Unit, onFailure: Runnable) {...

然后将userName传递给回调:

NetworkManager.instance.performCall(NetworkManager.REGISTRATION.verifyUser(id),
                object : NetworkManager.OnRequestCallback<UserInfoResponse> {
                    override fun onSuccess(body: UserInfoResponse?) {
                        body?.data?.let {
                            onSuccess.invoke(it.userName) // Pass userName
                        }
                    }

                    override fun onError(errorBody: String?) {
                        onFailure.run()
                    }
                })
    }

然后您可以从此回调中获取用户名:

objectManager.callVerifyAdvisor(
          {userName -> } // Here you get your result
          Runnable {[On Error]}
}