在SQL中为多个ID计算单独的百分比值

Question

我有一个表，其中包含CitrixID，Wave，DocNumber，不正确，正确和百分比列

如何获取多个CitrixID的单独百分比值？

我在sql中编写了以下查询，但返回的百分比值错误。

 SELECT Citrix_ID, Wave,Document_Number, SUM(Attempt) as Incorrect,SUM(AttemptGreen) as Correct, 
         CONCAT((SUM(AttemptGreen) *100 / (SELECT SUM(AttemptGreen) + SUM(Attempt) FROM tblTrackQuestErrors WHERE Wave='Wave 86' and Document_Number='0123123123116')),'%')  AS Percentage  
         FROM tblTrackQuestErrors WHERE Wave='Wave 86' and Document_Number='0123123123116' group by Citrix_ID,Wave,Document_Number

我需要输出如下所示

Answer 1

Sudhakar，请您参考以下选择和百分比计算

select
    convert(
        decimal(5,2), 
        isnull(correct,0) * 100.0 / case when (isnull(correct,0) + isnull(incorrect,0)) = 0 
                                        then null 
                                        else (isnull(correct,0) + isnull(incorrect,0)) 
                                    end
    ) as [percentage]
from tbl

Answer 2

我没有您的桌子，但这应该可以工作

SELECT Citrix_ID, Wave,Document_Number, SUM(Attempt) as Incorrect, SUM(AttemptGreen) as Correct
, SUM(AttemptGreen) *100 / SUM(AttemptGreen) + SUM(Attempt) AS Percentage
,MIN((
  SELECT SUM(T1.AttemptGreen) *100 / SUM(T1.AttemptGreen) + SUM(T1.Attempt) 
  FROM   tblTrackQuestErrors T1
  WHERE  T1.Wave            = tblTrackQuestErrors.Wave
  AND    T1.Document_Number = tblTrackQuestErrors.Document_Number
)) AS Percentage_Multi_CitrixID
FROM   tblTrackQuestErrors
group by Citrix_ID,Wave,Document_Number

Answer 3

选择Citrix_ID，Wave，Document_Number，错误的SUM（Attempt），正确的SUM（AttemptGreen），         CONCAT（CONVERT（DECIMAL（5,2），SUM（AttemptGreen）* 100.0 /案例（SUM（AttemptGreen）+ SUM（Attempt））= 0 THEN NULL ELSE（SUM（AttemptGreen）+ SUM（Attempt））END）， '％'）作为[百分比]
        FROM tblTrackQuestErrors WHERE Wave = @ Wave和Document_Number = @ Document_Number组，按Citrix_ID，Wave，Document_Number