Question

我试图将一组对象合并成一个对象，作为一个对象放在列表的末尾。有什么办法可以实现？

我尝试对.append使用多个参数，并尝试搜索其他函数，但到目前为止我还没有发现任何东西。

yourCards = []
cards =["Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"]
suits = ["Hearts","Diamonds","Clubs","Spades"]

yourCards.append(cards[random.randint(0,12)],"of",suits[random.randint(0,3)])

我希望列表中仅包含一个新元素，例如“两颗心”，但我却收到此错误：

TypeError: append() takes exactly one argument (3 given)

Answer 1

您正在发送append()多个参数而不是字符串。这样将参数格式化为字符串。同样，{@ {1}}比random.choice()更好，如下面的@JaSON所述。

3.6+，使用random.randint()

f-strings

使用yourCards.append(f"{random.choice(cards)} of {random.choice(suites)}")

.format()

字符串串联

yourCards.append("{} of {}".format(random.choice(cards), random.choice(suites)))

改进Alex的yourCards.append(str(random.choice(cards)) + " of " + str(random.choice(suites))) #You likely don't need the str() but it's just a precaution方法

join()

Answer 2

yourCards.append(' '.join([random.choice(cards), "of", random.choice(suits)]))

尝试对.append使用多个参数吗？

2 个答案: