我需要编写类型转换器以将ArrayList保存为列。我曾尝试编写转换器,但没有结果,我收到此错误:
“错误:不确定如何将游标转换为此方法的返回类型”
@Entity(tableName = "WeightRecords")
class WeightRecords : Serializable {
@PrimaryKey(autoGenerate = true)
var id: Long = 0
@ColumnInfo(name = "weightRecords")
var weightRecords: Double = 0.0
@ColumnInfo(name = "days")
var days: String = ""
@ColumnInfo(name = "data")
var data: ArrayList<Float>? = ArrayList()
}
@Dao
abstract class WeightRecordDao : BaseDao<WeightRecords>() {
@Insert(onConflict = OnConflictStrategy.REPLACE)
abstract fun insertWeightRecords(weightRecords: WeightRecords): Long
@Query("SELECT data FROM WeightRecords")
abstract fun getData(): ArrayList<Float>
}
我需要写类型转换器,请帮忙!
答案 0 :(得分:0)
好吧,回答您的问题,我想应该是这样的
@TypeConverter
fun fromArrayListOfFloats(list: ArrayList<Float>?): String {
return list?.joinToString(separator = ";") { it.toString() } ?: ""
}
@TypeConverter
fun toArrayListOfFloats(string: String?): ArrayList<Float> {
return ArrayList(string?.split(";")?.mapNotNull { it.toFloatOrNull() } ?: emptyList())
}
但是也许存储floats
的列表对您来说不是最好的方法?也许您应该创建单独的记录表,其中每个float
都将作为单独的行?
此外,我想,如果每行都有ArrayList<Float>
,则您的getData
方法应该返回List<ArrayList<Float>>
...