如何在GridView中添加图像?我正在从API获取网格数据,但想将图像添加到该gridView

时间:2019-01-11 10:37:07

标签: android gridview imageview

我在项目中使用网格视图。我正在从API获取数据。但是我想将图像添加到该网格。下面给出的代码是适配器类代码

 @Override
        public View getView(final int position, View convertView, ViewGroup parent) {

        inflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

        ViewHolder mHolder = new ViewHolder();

        ImageView imageView;
        if (convertView == null) {



            convertView = inflater.inflate(R.layout.adapter_category, null);
            mHolder.tvCategoryName = (TextView) convertView.findViewById(R.id.tvCategoryName);
            mHolder.tvCategoryDescription = (TextView) convertView.findViewById(R.id.tvCategoryDescription);
            mHolder.ivItemImage = (ImageView) convertView.findViewById(R.id.ivItemImage);

            convertView.setTag(mHolder);
        } else {
            mHolder = (ViewHolder) convertView.getTag();

        }

        mHolder.tvCategoryName.setText(getItem(position).getName());
        mHolder.tvCategoryDescription.setText("");
        mHolder.ivItemImage.setImageResource(mThumbIds[4]);


        convertView.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {

                Log.e("THIS IS CATEGORY TYPE", mCategoryType + "");

                if (mCategoryType == ConstantsInternal.categoryType.MainCategory.getValue()) {
                    Log.e("RENT", "MAINCATEGORY");
                    Bundle mBundle = new Bundle();
                    mBundle.putString("itemName", getItem(position).getName());
                    Log.e("MAINCATEGORY", getItem(position).getName());
                    MyActivity.getInstance().subcategory(mContext, mBundle);
                }


            }
        });

        return convertView;

    }

    private Integer[] mThumbIds = {
            R.drawable.camera ,R.drawable.ic_cart, R.drawable.commericalvehicles, R.drawable.garments
    };

我的预期结果是我想要Gridview中的图像。每个网格应该是不同的图像。我是新来的。提前致谢。

1 个答案:

答案 0 :(得分:0)

代替OnFailureListener

尝试

ResolvableApiException