<?php
// This is a code to check the username from a mysql database table
if(isSet($_POST['username']))
{
$username = $_POST['username'];
include("dbconnection.php");
$sql_check = mysql_query("SELECT user FROM {$prefix}users WHERE user='$username'");
if(mysql_num_rows($sql_check))
{
echo '<span style="color: red;">The username <b>'.$username.'</b> is already in use.</span>';
}
else
{
echo 'OK';
}}
?>
这是check.php女巫，我可以改变没有问题与CI一起工作，下面我需要帮助！
<script src="js/jquery.js" type="text/javascript">/script>
<script type="text/javascript">
pic1 = new Image(16, 16);
pic1.src = "loader.gif";
$(document).ready(function(){
$("#username").change(function() {
var usr = $("#username").val();
if(usr.length >= 3)
{
$("#status").html('<img align="absmiddle" src="loader.gif" /> Checking availability...');
$.ajax({
type: "POST",
url: "check.php",
data: "username="+ usr,
success: function(msg){
$("#status").ajaxComplete(function(event, request, settings){
if(msg == 'OK')
{
$("#username").removeClass('object_error'); // if necessary
$("#username").addClass("object_ok");
$(this).html(' <img align="absmiddle" src="accepted.png" /> ');
}
else
{
$("#username").removeClass('object_ok'); // if necessary
$("#username").addClass("object_error");
$(this).html(msg);
}});}});}
else
{
$("#status").html('The username should have at least 3 characters.');
$("#username").removeClass('object_ok'); // if necessary
$("#username").addClass("object_error");
}});});
//-->
</script>
我理解这个脚本正在做的大部分内容，我可以使它在普通的PHP中工作，但我使用的是代码点火器。如果我正确阅读它我应该只需要改变行url：“check.php”，当然原来的php可以让任何人指出我正确的方向吗？