Question

谢谢您的回答

我做到了：我使用了“ sync-mysql”：

但是现在非常慢...

也许我可以使用Mysql NPM做同样的代码您是否知道我要使用异步函数并执行以下相同操作时代码的外观？这将对我有很大帮助：）

我几乎完成了我的项目，只剩下这个功能了

     const  customer_booked = []
  customer_booked[0] = []
  customer_booked[1] = []

  let sql = "SELECT *  " +
      "FROM customer as C " +
      "WHERE customer_reference REGEXP '^[c]i*' "
  if (filters[0].value.length){
      sql += "AND C.customer_name LIKE '%" + filters[0].value + "%' "
  }

  if (filters[3].value.length){
      sql += "LIMIT " + filters[3].value
  }

  var result = connection.query(sql);
  const customers = [];


  const booked = connection.query('SELECT cr.customer_id, a.codeAgent ' +
      'FROM customer_reservation as cr ' +
      'INNER JOIN agent as a ' +
      'ON a.id = cr.agent_id')

  booked.forEach(customer_booking => {
      customer_booked[0].push(customer_booking.customer_id)
      customer_booked[1].push(customer_booking.codeAgent)
  });

  result.forEach( customer => {
      var months;

      let d1 = new Date(customer.last_order);

      let d2 = new Date();

      months = (d2.getFullYear() - d1.getFullYear()) * 12;
      months -= d1.getMonth() + 1;
      months += d2.getMonth();

      months = months <= 0 ? 0 : months;

      if (customer_booked[0].includes(customer.customer_id)){
          let code_agent_index = customer_booked[0].indexOf(customer.customer_id)
          customer.available = 'booked'
          customer._rowVariant = 'warning'
          customer.agent_code = customer_booked[1][code_agent_index]
      }
      else if (months >= 12){
          customer.available = 'available'
          customer._rowVariant = 'success'
      } else {
          customer.available = 'notAvailable'
          customer._rowVariant = 'danger'
      }

       let sql2 = "SELECT * " +
           "FROM customer_addresses AS CA " +
           "WHERE CA.customer_id = " + customer.id

      customer.addresses = connection.query(sql2)
      customers.push(customer);
      //customers[customers.length].push()




  })

  callback(false, result)

Answer 1

您可以使用async/await使用node.js IIFE，如下所示：

(async() => {
  const users = await getUsers();

  for(const user of users){
    user.addresses = await getAddresses(user.id);
    // your other code just translated to JS.
  }

  return users;
})()

因此，主要思想是await您的异步代码。
例如，我们使用IIFE（立即调用函数表达式）来访问所需的async/await并进行测试。
在实际代码中，您应该使用关键字async

命名函数

这里有不错的教程，可以解释如何使用异步/等待1，2

Mysql NodeJ同步查询

1 个答案: