Question

   public function returnsTrueIfEmailIsVerified(Request $request)
    {
        // Gets the email
        $email = request("email"); //johndoe@example.com for example
        // Determine if zero or one ;
        $user  = User::where('email','=',$email)->get(); // 0 or 1  ;

        $userCount  = User::where('email','=',$email)->count(); // 0 or 1  ;

        $confirmedValue = $user->get('confirmed');


        $response ;

        if ( $user === 1 && $confirmedValue === true ) {
            $response = 'OK';
        }
        elseif ($user === 1 && $confirmedValue === false) {
            $response = 'Not Confirmed yet';
        }
        else { 
            $response = 'Not Registered yet';
        }
        return response()->json(200,$response);

    }

使用该代码，我将返回一个响应：如果用户尚未注册或已注册，并且已经注册，但尚未确认，则为..

我想从中得到一些回报，我不仅仅熟悉laravel的方式

Answer 1

您的代码中有太多错误，我已将其修复，此代码将起作用。我认为您需要了解更多Laravel和PHP。

 rails g kaminari:views default

您不能将字符串作为json来响应，json是键值对。
public function returnsTrueIfEmailIsVerified(Request $request) { $email = request("email"); $user = User::where('email', '=', $email); $response = [ 'message' => '' ]; if ($user->count() === 1) { $confirmedValue = $user->first()->confirmed; if ($confirmedValue) { $response['message'] = 'OK'; } else { $response['message'] = 'Not Confirmed yet'; } } else { $response['message'] = 'Not Registered yet'; } return response()->json($response, 200); }返回不为0或1的查询生成器，请使用User::where('email', '=', $email)方法；
您无法从多个商品中获取价值，例如count()或使用Laravel特殊方法$user->get()[0]['confirmed]

如何从集合中获取变量的值

1 个答案: