如何弯曲图纸(立方体)?我想控制弯曲/曲线的角度。
例如
cube([50,50,2]);
答案 0 :(得分:2)
您可以rotate_extrude()
带有参数angle的矩形。这需要opencad版本2016.xx或更高版本,请参见documentation。
必须安装开发快照,请参见download openscad
$fn= 360;
width = 10; // width of rectangle
height = 2; // height of rectangle
r = 50; // radius of the curve
a = 30; // angle of the curve
rotate_extrude(angle = a) translate([r, 0, 0]) square(size = [height, width], center = true);
看起来像这样:
曲线由半径和角度定义。我认为在此草图中使用其他尺寸(例如长度或dh)更为现实
并计算半径和角度
$fn= 360;
w = 10; // width of rectangle
h = 2; // height of rectangle
l = 25; // length of chord of the curve
dh = 2; // delta height of the curve
module curve(width, height, length, dh) {
// calculate radius and angle
r = ((length/2)*(length/2) - dh*dh)/(2*dh);
a = asin((length/2)/r);
rotate_extrude(angle = a) translate([r, 0, 0]) square(size = [height, width], center = true);
}
curve(w, h, l, dh);
答案 1 :(得分:1)
我可以这样做,但是如果您可以将#degrees中的弯曲/曲线指定为函数的参数,那会更好:
$fn=300;
module oval(w, h, height, center = false) {
scale([1, h/w, 1]) cylinder(h=height, r=w, center=center);
}
module curved(w,l,h) {
difference() {
oval(w,l,h);
translate([0.5,-1,-1]) color("red") oval(w,l+2,h+2);
}
}
curved(10,20,30);
答案 2 :(得分:0)
使用a_manthey_67所使用的概念,校正数学并将居中对象(将弦与y轴对齐)居中:
module bentCube(width, height, length, dh) {
// calculate radius and angle
r = (length*length + 4*dh*dh)/(8*dh);
a = 2*asin(length/(2*r));
translate([-r,0,0]) rotate([0,0,-a/2])
rotate_extrude(angle = a) translate([r, 0, 0]) square(size = [height, width], center = true);}
答案 3 :(得分:0)
或者,如果您只想要固定长度且具有一定弯曲角度的东西,请执行以下操作:
module curve(width, height, length, a) {
if( a > 0 ) {
r = (360 * (length/a)) / (2 * pi);
translate( [-r-height/2,0,0] )
rotate_extrude(angle = a)
translate([r, 0, 0])
square(size = [height, width], center = false);
} else {
translate( [-height/2,0,width] )
rotate( a=270, v=[1,0,0] )
linear_extrude( height = length )
square(size = [height, width], center = false);
}
}
当弯曲角度为0时,需要使用if (a > 0)
语句作为例外(如果绘制曲面,则将导致无限半径)。