Question

我正在从Julia版本1.0.2（2018-11-08）的数据框中构建元组数组

在Julia的早期版本中，我能够使用DataArray创建元组数组，如下所示：

df是我的数据框，p_1至p_30是所选列

NULL

但是，现在出现错误：FULL JOIN

我现在正在尝试使用for循环构建一个元组数组，但是，这不起作用。

tuple.array= collect(zip(df[:p_1], convert(DataArray, df[:p_2]),df[:p_3], df[:p_4], df[:p_5],df[:p_6], df[:p_7], df[:p_8], df[:p_9], df[:p_10],df[:p_11], 
df[:p_12], df[:p_13], df[:p_14],df[:p_15],df[:p_16],df[:p_17],df[:p_18], df[:p_19],df[:p_20],df[:p_21],df[:p_22],df[:p_23],df[:p_24],df[:p_25],
df[:p_26], df[:p_27],df[:p_28], df[:p_29], df[:p_30]))

结果应如下所示：

UndefVarError: DataArray not defined

它看起来好像没有合并元组，而是输出：

k = [] 

function f(x, 
k::Array{Tuple{Int64,Float64,Float64,Float64,Int64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,String,Float64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,String,Int64,Float64,String},1}
)
   for i = 1:2

       a = x[i,1], x[i,2], x[i,3], x[i,4], x[i,5], x[i,6], x[i,7], x[i,8], 
       x[i,9], x[i,10], x[i,11], x[i,12], x[i,13], x[i,14], x[i,15], x[i,16], 
       x[i,17], x[i,18], x[i,19], x[i,20], x[i,21], x[i,22], x[i,23],  x[i,24], 
       x[i,25], x[i,26], x[i,27], x[i,28], x[i,29], x[i,30]

       k[i] = a

   end 

   k

end 

ans = f(df)

[(1, 35455.87, 5.5, 4.5, 83, 0.06, 0.000166, 4.0e-5, 2.45e-9, 5.93e-11, 0.25, 0.01851, 0.33, 0.5, 0.01851, "FC", 258.129, 90, 0, 120, 240, 360, 420, 0, 0, 5000, "10/12/2017", 54, 0.1, "TRUE"),(2, 1.05e6, 4.75, 4.0, 83, 0.06, 0.000125, 2.95e-5, 1.85e-9, 5.88e-11, 0.25, 0.01851, 0.33, 0.5, 0.01851, "FC", 258.129, 90, 0, 120, 240, 360, 420, 0, 0, 5000, "10/12/2017", 54, 0.1, "TRUE")] Array{Tuple{Int64,Float64,Float64,Float64,Int64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,Float64,String,Float64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,Int64,String,Int64,Float64,String},1}似乎是我数据框的大小

(1, 35455.87, 5.5, 4.5, 83, 0.06, 0.000166, 4.0e-5, 2.45e-9, 5.93e-11, 0.25, 0.01851, 0.33, 0.5, 0.01851, "FC", 258.129, 90, 0, 120, 240, 360, 420, 0, 0, 5000, "10/12/2017", 54, 0.1, "TRUE")
(2, 1.05e6, 4.75, 4.0, 83, 0.06, 0.000125, 2.95e-5, 1.85e-9, 5.88e-11, 0.25, 0.01851, 0.33, 0.5, 0.01851, "FC", 258.129, 90, 0, 120, 240, 360, 420, 0, 0, 5000, "10/12/2017", 54, 0.1, "TRUE")

(4, 30)

Answer 1

这是将DataFrame转换为元组数组的方法：

julia> df = DataFrame(rand(4,5))
4×5 DataFrame
│ Row │ x1       │ x2       │ x3       │ x4       │ x5         │
│     │ Float64  │ Float64  │ Float64  │ Float64  │ Float64    │
├─────┼──────────┼──────────┼──────────┼──────────┼────────────┤
│ 1   │ 0.672177 │ 0.946374 │ 0.595168 │ 0.722334 │ 0.00143513 │
│ 2   │ 0.705244 │ 0.34661  │ 0.679062 │ 0.19639  │ 0.665722   │
│ 3   │ 0.714121 │ 0.25532  │ 0.334179 │ 0.796099 │ 0.31926    │
│ 4   │ 0.915351 │ 0.101242 │ 0.241781 │ 0.497605 │ 0.255265   │

julia> values.(eachrow(df)) # option 1
4-element Array{NTuple{5,Float64},1}:
 (0.6721769645742341, 0.9463742907744139, 0.5951678416468196, 0.7223337537204884, 0.0014351278761846054)
 (0.7052438908128555, 0.34661004784791927, 0.6790618125985046, 0.19639048780237434, 0.6657217151376063)
 (0.7141207500236866, 0.2553202507731116, 0.33417888761790393, 0.7960990393316545, 0.31926035845300627)
 (0.9153512246404232, 0.10124180902852187, 0.24178081071551794, 0.49760454756012784, 0.2552649323458289)

julia> Tuple.(eachrow(df)) # option 2
4-element Array{NTuple{5,Float64},1}:
 (0.6721769645742341, 0.9463742907744139, 0.5951678416468196, 0.7223337537204884, 0.0014351278761846054)
 (0.7052438908128555, 0.34661004784791927, 0.6790618125985046, 0.19639048780237434, 0.6657217151376063)
 (0.7141207500236866, 0.2553202507731116, 0.33417888761790393, 0.7960990393316545, 0.31926035845300627)
 (0.9153512246404232, 0.10124180902852187, 0.24178081071551794, 0.49760454756012784, 0.2552649323458289)

朱莉娅元组数组

1 个答案: