EID JOINING_DT
---------
1 04/04/2018
2 06/06/2018
3 04/04/2018
4 03/03/2018
tab2:
EID JOINING_DT INFO
-------------------
1 01/01/2018 x
1 02/02/2018 x
1 03/03/2018 x
1 04/04/2018 x
1 05/05/2018 x
2 01/01/2018 x
2 05/05/2018 x
2 07/07/2018 x
3 02/02/2018 x
4 03/03/2018 x
通过使用以上2个表,我想获取t1.id = t2.d,并且t1的日期应该恰好在前,相等且都更大。像下面 结果:
EID JOINING_DT INFO
-------------------
1 03/03/2018 x
1 04/04/2018 x
2 01/01/2018 x
2 05/05/2018 x
2 07/07/2018 x
3 02/02/2018 x
4 03/03/2018 x
注意:请考虑该解决方案应该是具有大量数据的高性能
答案 0 :(得分:0)
也许这就是您想要的
select id, date,
value from
table1 t1 join
table2 t2 on
( t1.id =t2.id )
and
(abs(t2.date-t1.date) =1
or
t1.date=t2.date)