我想将同一天的doc_type分组在一起。例如,如果'1099'doc_type在2018-12-12上被分类了两次。我想对它们进行两次计数,并将频率显示为2。
这是我的查询。我应该在doc_type和date相等的条件下对表执行自我连接吗?
SELECT cast(date_parse(date_time, '%Y/%m/%d %H:%i:%s') AS date) AS Date
, json_array_get (doc_type, 0) AS doc_type
, COUNT(DISTINCT doc_type) as Frequency
FROM "reports"."dev_operator_logs"
WHERE doc_type IS NOT NULL
GROUP BY date_time, doc_type
ORDER BY date_time;
答案 0 :(得分:0)
也许您只是想按date
分组而不是datetime
并删除doc_type
?
SELECT cast(date_parse(date_time, '%Y/%m/%d') AS date) AS Date,
json_array_get(doc_type, 0) AS doc_type,
COUNT(DISTINCT doc_type) as Frequency
FROM "reports"."dev_operator_logs"
WHERE doc_type IS NOT NULL
GROUP BY cast(date_parse(date_time, '%Y/%m/%d') AS date)
ORDER BY cast(date_parse(date_time, '%Y/%m/%d') AS date);