Question

这是程序。有人可以告诉我我做错了什么吗？每次我为字符串SolvingFor输入值时，程序都会崩溃。我是编码的新手，所以如果我犯了一个愚蠢的错误，请告诉我。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace PercentageCalculator
{
class Program
{
    static void Main(string[] args)
    {
        string SolvingFor;
        int part;
        int whole;
        int percent;
        Console.WriteLine("please only use numbers and lowercase letters.");
        Console.WriteLine("Are you trying to solve for percent, part, or           whole?");
         SolvingFor = Convert.ToString(Console.Read());

        if (SolvingFor == "part") {
            Console.WriteLine("Please Enter Value of the Whole");
            whole = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Please Enter Value of the Percent");
            percent = Convert.ToInt32(Console.ReadLine()); ;
            Console.WriteLine("Your answer is" + (whole * percent) / 100); }

       else if (SolvingFor == "whole")
        {
            Console.WriteLine("Please Enter Value of the part");
            part = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Please Enter Value of the Percent");
            percent = Convert.ToInt32(Console.ReadLine()); ;
            Console.WriteLine("Your answer is" + (part * 100) / percent);
        }


        else if (SolvingFor == "percent")
        {
            Console.WriteLine("Please Enter Value of the part");
            part = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Please Enter Value of the whole");
            whole = Convert.ToInt32(Console.ReadLine()); ;
            Console.WriteLine("Your answer is" + (part * 100) / whole);
        }

        else
        {
            Console.WriteLine("Please only input valid lowercase letters and numbers. ");
        };
        Console.Read();
    }
    }
}

Answer 1

        //SolvingFor = Convert.ToString(Console.Read());
        SolvingFor = Convert.ToString(Console.ReadLine());

如果将鼠标悬停在ReadLine上

您将看到它返回一个字符串，因此不需要 Convert.ToString

        SolvingFor = Console.ReadLine();

Answer 2

第一期：代码下方的一行仅读取一个字符。

使用Console.Read()代替Console.ReadLine()，使您可以输入多个字符。

 SolvingFor = Convert.ToString(Console.Read());

第二期：您正在使用Convert.ToInt32(Console.Readline());

请注意，Convert.ToInt32会在输入提供的数字以外的任何内容上引发异常。

最好使用int.TryParse来返回转换是否成功。

当向我的程序输入值时，它崩溃:( C＃

2 个答案: