是否可以在node.js函数中定义全局变量?
我想在其他函数中使用ko变量(在getNumbers函数中声明)
function getNumbers(callback) {
result = cio.query("SELECT numbers FROM rooms WHERE durum='1'", function (err, result) {
if (err) throw err;
callback((result.length > 0) ? result[0].numbers : "");
});
}
var ko = getNumbers(function (result) {
console.log(result)
});
var zo = ko;
“未定义”
46,16,55,12,74,48,77,42,4,29,14,81,13,35,39,85,7,54,27,66,41,9,17,82,31,21,57,79,62,56,11,49,3,33,64,8,83,88,61,18,58,63,51,90,22,71,67,69,75,6,2,34,30,25,38,28,68,5,50,15,87,19,65,36,45,24
C:\wamp64\www\node\st\rooms.js:497
var datadad = zo[Math.floor(Math.random()*zo.length)];
^
TypeError: Cannot read property 'length' of undefined
at sayiver (C:\wamp64\www\node\st\rooms.js:497:54)
at Timeout._onTimeout (C:\wamp64\www\node\st\rooms.js:513:5)
at ontimeout (timers.js:436:11)
at tryOnTimeout (timers.js:300:5)
at listOnTimeout (timers.js:263:5)
at Timer.processTimers (timers.js:223:10)
答案 0 :(得分:2)
可以,而且您的方法正确。
未定义public class MilitaryPerson
{
public string ImageUrl { get; set; }
public string MilitaryNumber { get; set; }
public string FirstName { get; set; }
public string FatherName { get; set; }
public string LastName { get; set; }
public string TitleName { get; set; }
public string MainCategoryName { get; set; }
public string CategoryTypeName { get; set; }
public string RegimentName { get; set; }
public string Address { get; set; }
public string ChemiseSize { get; set; }
public string SuitSize { get; set; }
public bool WithWeap { get; set; }
public string WithWeapon { get; set; }
public int? ForceID { get; set; }
public bool IsImported { get; set; }
}
//JS Code
var Result = [];
var ExcelToJSON = function () {
this.parseExcel = function (file) {
var reader = new FileReader();
reader.onload = function (e) {
var data = e.target.result;
var workbook = XLSX.read(data, {
type: 'binary'
});
workbook.SheetNames.forEach(function (sheetName) {
// Here is your object
var XL_row_object =XLSX.utils.sheet_to_row_object_array(workbook.Sheets[sheetName]);
var json_object = JSON.stringify(XL_row_object);
if (JSON.parse(json_object).length > 0) {
Result = JSON.parse(json_object);
Result = Result.splice(1, Result.length);
//console.log(Result);
}
}
(和ko
)的原因是因为您没有从zo
返回任何信息,而是使用了回调。
要么处理涉及回调内部变量的逻辑,要么使用getNumbers
和async
。
答案 1 :(得分:2)
这是您的代码的快速修复。如前所述,由于您没有从函数中返回此值,因此必须在回调内部处理此逻辑。同样,即使您返回一个值,ko仍将是未初始化的(当您尝试将其值分配给zo时),因为您使用异步操作从DB中获取了一些东西,并且您不必等待数据就可以分配。
function getNumbers(callback) {
result = cio.query("SELECT numbers FROM rooms WHERE durum='1'", function (err, result) {
if (err) throw err;
callback((result.length > 0) ? result[0].numbers : "");
});
}
var ko;
var zo;
getNumbers(function (result) {
ko = result;
console.log(result);
zo = ko;
});
下面是一个代码示例,其中zo仍将是未定义的(假定功能当然不是同步的):
function getNumbers(callback) {
result = cio.query("SELECT numbers FROM rooms WHERE durum='1'", function (err, result) {
if (err) throw err;
callback((result.length > 0) ? result[0].numbers : "");
});
}
var ko;
getNumbers(function (result) {
ko = result;
console.log(result);
});
var zo = ko; //Not good!
答案 2 :(得分:0)
您可以使用这种方法:
global.ko; // Declaration of the global variable - undefined
global.ko = 5; // Global variable initialized to value 5.
您可以这样访问:
var myNumber = global.myNumber;