演示

Question

该代码应将10次翻转的大部分奖励给获胜者硬币一侧。但是，它只会进行9次翻转，并奖励9次中的大多数。

我尝试调整数字，但没有一个成功。将百分比更改为110后，总的翻转次数仅为7

    //start decleration of variables; self explainitory 
    var placeholder = document.getElementById("placeholder");
    var heads_counter = 0;
    var tails_counter = 0;
    var wins = 10;

    //reset button listener & functionality 
    document.getElementById("reset").addEventListener("click", function(){
        heads_counter = 0;
        tails_counter = 0;
        placeholder.innerText = ("");
        coin_placeholder.innerText = ("");
    });

    //coin img event listener & functionality 
    document.getElementById("coin").addEventListener("click", function(){
        //50% chance of 1 or 2
        var chance = Math.floor(Math.random() * 2); 

        //if chance is 1 "Heads!"" is displayed in place holder and adds to heads_counter
        if (chance == 1){
            placeholder.innerText = ("Heads!");
            heads_counter++;                
        //else statment if chance is 2, "Tails!" is displayed and adds to tails_counter 
        }else  {
            placeholder.innerText = ("Tails!");
            tails_counter++;        
        }
        //if the majority of total flips is heads, "Heads wins!" is displayed
        if(51 <= heads_counter / wins * 100 && tails_counter / wins * 100 <= 49){
            placeholder.innerText = ("Heads Wins!");
            heads_counter = 0;
            tails_counter = 0;
        //if the majority of total flips is tails, "Tails wins!" is displayed
        }else if (51 <= tails_counter / wins * 100  && heads_counter / wins * 100 <= 49){
            placeholder.innerText = ("Tails Wins!");
            heads_counter = 0;
            tails_counter = 0;
        //if flips are tied, "Tie!" is displayed
        }else if(tails_counter / wins * 100 == 50 && heads_counter / wins * 100 == 50){
            placeholder.innerText = ("Tie!")
            heads_counter = 0;
            tails_counter = 0;
        }
        //innerText of coin_placeholder
        coin_placeholder.innerText = ("Heads: " + heads_counter + " Tails: " + tails_counter);
});

Answer 1

掷硬币没有发生十次。

您在第二条if语句中的逻辑实际上是在一侧寻找5个或更多的翻转，但不检查所需的余数。即即使只有1个尾巴，也将有6个正面获胜并结束比赛。

这是因为大于和小于需求不一定总和为100％，即6个正面和3个反面将满足这些要求，因为60％为正面，而30％为反面（即> 51％正面和反面<49％）。

我添加了基本检查，如果尚未达到整体限制，则退出此检查之前的功能。

演示

//start decleration of variables; self explainitory 
var placeholder = document.getElementById("placeholder");
var coin_placeholder = document.getElementById("coin_placeholder");
var heads_counter = 0;
var tails_counter = 0;
var wins = 10;

//reset button listener & functionality 
document.getElementById("reset").addEventListener("click", function() {
  heads_counter = 0;
  tails_counter = 0;
  placeholder.innerText = ("");
  coin_placeholder.innerText = ("");
});

//coin img event listener & functionality 
document.getElementById("coin").addEventListener("click", function() {
  //50% chance of 1 or 2
  var chance = Math.floor(Math.random() * 2);

  //if chance is 1 "Heads!"" is displayed in place holder and adds to heads_counter
  if (chance == 1) {
    placeholder.innerText = ("Heads!");
    heads_counter++;
    //else statment if chance is 2, "Tails!" is displayed and adds to tails_counter 
  } else {
    placeholder.innerText = ("Tails!");
    tails_counter++;
  }

  //innerText of coin_placeholder
  coin_placeholder.innerText = ("Heads: " + heads_counter + " Tails: " + tails_counter);
  
   // Check if total coin flips matches the required number of wins, exit function if it does not
   if ( heads_counter + tails_counter < wins ) {
      return;
   }

  //if the majority of total flips is heads, "Heads wins!" is displayed
  if (51 <= heads_counter / wins * 100 && tails_counter / wins * 100 <= 49 ) {
    placeholder.innerText = ("Heads Wins!");
    //if the majority of total flips is tails, "Tails wins!" is displayed
  } else if (51 <= tails_counter / wins * 100 && heads_counter / wins * 100 <= 49 ) {
    placeholder.innerText = ("Tails Wins!");
    //if flips are tied, "Tie!" is displayed
  } else if (tails_counter / wins * 100 == 50 && heads_counter / wins * 100 == 50 ) {
    placeholder.innerText = ("Tie!")
  }
  
  // This can come out of the if statement above now\
  // Reset counters
  heads_counter = 0;
  tails_counter = 0;
  
});

<p id="placeholder"></p>
<p id="coin_placeholder"></p>

<button id="reset">Reset</button>
<button id="coin">Coin</button>

if语句的逻辑仅达到9/10

1 个答案:

演示