如何在javascript

Question

我有一个名为files的数组：

        files = [
            {
                id: "1", 
                title: "aras", 
                price: 100, 
                size: 25, 
                tools: [
                    "Hammer",
                    "Zip",
                    "Line",
                    "Nexti"
                    ]
            },
            {
                id: "2", 
                title: "yasio", 
                price: 150, 
                size: 30, 
                tools: [
                    "Hammer",
                    "Zip",
                    ]
            },
            {
                id: "3", 
                title: "janio", 
                price: 200, 
                size: 30, 
                tools: [
                    "Line",
                    "Nexti"
                    ]
            },
            {
                id: "4", 
                title: "chashio", 
                price: 400, 
                size: 35, 
                tools: [
                    "Nexti"
                    ]
            },



          ]

例如，我要过滤此对象以获取数组：90至150之间的价格和25至40之间的尺寸以及包含{ {1}}和Hammer。 输出必须为：

Zip

我该怎么做？

Answer 1

files.filter(function(file){
            return ((file.price>= 90 && file.price<=150) && (file.size >= 25 && file.size <= 40))
    })

Answer 2

您需要使用Array.prototype.filter()返回满足以下条件的项目：

(price>=90 && price <= 150) && (size >= 25 && size <= 40)

var files = [
  {id: "1", title: "aras", price: 100, size: 25, tools: ["Hammer","Zip","Line","Nexti"] },
  {id: "2", title: "aras", price: 150, size: 30, tools: ["Hammer","Zip"]},
  {id: "3", title: "aras", price: 160, size: 35, tools: ["Line","Nexti"]},
  {id: "4", title: "aras", price: 90,  size: 40, tools: ["Nexti"]},
  {id: "5", title: "aras", price: 200, size: 45, tools: []}
]

var res = files.filter(f => (f.price>=90 && f.price <= 150) 
                         && (f.size >= 25 && f.size <= 40) 
                         && (f.tools.includes('Hammer') &&  f.tools.includes('Zip')));

console.log(res);