Question

我有一个句子列表，我想创建跳过图(window size = 3)，但我不要，因为计数器之间没有关联，所以希望计数器跨句子。

因此，如果我有以下句子：

[["my name is John"] , ["This PC is black"]]

三胞胎将是：

[my name is]
[name is john]
[this PC is]
[PC is black]

最好的方法是什么？

Answer 1

这是一个简单的功能。

def skipgram(corpus, window_size = 3):
    sg = []
    for sent in corpus:
        sent = sent[0].split()
        if len(sent) <= window_size:
            sg.append(sent)
        else:
            for i in range(0, len(sent)-window_size+1):
                sg.append(sent[i: i+window_size])
    return sg

corpus = [["my name is John"] , ["This PC is black"]]
skipgram(corups)

Answer 2

尝试一下！

from nltk import ngrams

def generate_ngrams(sentences,window_size =3):
    for sentence in sentences:
        yield from ngrams(sentence[0].split(), window_size)

sentences= [["my name is John"] , ["This PC is black"]]

for c in generate_ngrams(sentences,3):
    print (c)

#output:
('my', 'name', 'is')
('name', 'is', 'John')
('This', 'PC', 'is')
('PC', 'is', 'black')

Answer 3

您实际上并不是真的想要skipgram，而是想要按大小划分一个块，请尝试以下操作：

from lazyme import per_chunk

tokens = "my name is John".split()
list(per_chunk(tokens, 2))

[输出]：

[('my', 'name'), ('is', 'John')]

如果要滚动窗口，即ngrams：

from lazyme import per_window

tokens = "my name is John".split()
list(per_window(tokens, 2))

[输出]：

[('my', 'name'), ('name', 'is'), ('is', 'John')]

在NLTK中同样适用于ngram：

from nltk import ngrams

tokens = "my name is John".split()
list(ngrams(tokens, 2))

[输出]：

[('my', 'name'), ('name', 'is'), ('is', 'John')]

如果您想要实际的跳过图，请How to compute skipgrams in python?

from nltk import skipgrams

tokens = "my name is John".split()
list(skipgrams(tokens, n=2, k=1))

[输出]：

[('my', 'name'),
 ('my', 'is'),
 ('name', 'is'),
 ('name', 'John'),
 ('is', 'John')]

如何为句子列表创建窗口/块？

3 个答案: