Question

我对Google People API的承诺。一个地图和过滤器可以完美地在两个元素上使用，但是在我觉得相同的第三个元素上却出现 undefined 错误。 >

我已阅读了在地图和过滤器上可以找到的所有内容，并进行了最后两个小时的有根据的猜测。两种方法似乎都无法促进我的努力。

resource_LBL，names_LBL和email_LBL有效。该代码在gender_LBL上失败。

const arr = this.k4kItems.map(item => ({
  resource_LBL: item.person.resourceName,
  names_lbl: item.person.names.filter(
    name_PARM => name_PARM.metadata.source.type === "CONTACT"
  ),
  email_LBL: item.person.emailAddresses.filter(
    email_PARM => email_PARM.metadata.source.type === "CONTACT"
  ),
  gender_LBL: item.person.genders.filter(
    gender_PARM => gender_PARM.metadata.source.type === "CONTACT"
  )
}))

以下是相关元素或JSON.Stringify（promise）的承诺。

"person": {
  "resourceName": "people\/c224283231105155344",
  "names": [
    {
      "metadata": {
        "primary": true,
        "source": {
          "type": "CONTACT",
          "id": "31cd0690f198110"
        }
      },
      "displayName": "Armena Kopf",
      "familyName": "Kopf",
      "givenName": "Armena",
      "displayNameLastFirst": "Kopf, Armena"
    },
    {
      "metadata": {
        "source": {
          "type": "PROFILE",
          "id": "112242108723070860293"
        }
      },
      "displayName": "Armena Dickson",
      "familyName": "Dickson",
      "givenName": "Armena",
      "displayNameLastFirst": "Dickson, Armena"
    }
  ],
  "genders": [
    {
      "metadata": {
        "primary": true,
        "source": {
          "type": "CONTACT",
          "id": "31cd0690f198110"
        }
      },
      "value": "female",
      "formattedValue": "Female"
    },
    {
      "metadata": {
        "source": {
          "type": "PROFILE",
          "id": "112242108723070860293"
        }
      },
      "value": "female",
      "formattedValue": "Female"
    }
  ],
  "emailAddresses": [
    {
      "metadata": {
        "primary": true,
        "source": {
          "type": "CONTACT",
          "id": "31cd0690f198110"
        }
      },
      "value": "armena_d@yahoo.com",
      "type": "home",
      "formattedType": "Home"
    }
  ]

预期结果是性别将映射到数组，而不是给出和 undefined 错误。

Answer 1

只需添加对可能不存在的深层属性的检查

gender_LBL: item.person.genders && item.person.genders.filter(
    gender_PARM => gender_PARM.metadata.source.type === "CONTACT"
)

Map和Filter在两个数组元素上起作用，但在第三个看起来相同的数组元素上失败

1 个答案: