laravel-5.7/mysql
在我的数据库中,我有一个像这样的json格式字段:
字段名称:功能:
[
{"id": 1, "url": null, "name": "A"},
{"id": 2, "url": null, "name": "B"}
]
我也在它的模型中写了这个
protected $casts = [
'features' => 'array'
];
现在我创建一个数组:
$features = array();
temp = array();
temp['id'] = 1;
temp['url'] = null;
temp['name'] = A;
$features[] = temp;
temp = array();
temp['id'] = 2;
temp['url'] = null;
temp['name'] = B;
$features[] = temp;
如何比较数据库中的$features array
和features field
?
ّ我检查了这些:
$fff = \App\Cart::whereFeatures($features)->get()->first();
或
$fff = \App\Cart::whereFeatures(json_encode($features))->get()->first();
或
$fff = \App\Cart::whereFeatures(json_encode($features,JSON_UNESCAPED_UNICODE))->get()->first();
答案 0 :(得分:1)
使用原始表达式强制转换比较值:
$fff = \App\Cart::whereRaw('features = cast(? as json)', json_encode($features))->get();