Question

这是我要序列化的类。

public class ItemRow<T> {

    private String id;
    private List<T> items;
}

允许使用两种变体。 ItemRow<String>, ItemRow<ItemRow>。在后一种情况下，它将被嵌套。

例如：

ItemRow item1 = new ItemRow("abc", Arrays.asList("item1", "item2", "item3"));
String result = mapper.writeValueAsString(item1);
System.out.println(result);

应该给予

{
     "abc":["item1","item2","item3"]
}

现在，后一种情况

ItemRow item2 = new ItemRow("cde", Arrays.asList("item4, item5"));
ItemRow item = new ItemRow("combined", Arrays.asList(item1,item2));
result = mapper.writeValueAsString(item);
System.out.println(result);

应该给予

{
    "combined": {
        "abc": ["item1", "item2", "item3"],
        "cde": ["item4", "item5"]
    }
}

但是序列化后者时出现异常。第一个按预期工作。所以我认为递归序列化失败了，但是我无法找出原因

这是例外

com.fasterxml.jackson.core.JsonGenerationException: Can not start an object, expecting field name (context: Object)

    at com.fasterxml.jackson.core.JsonGenerator._reportError(JsonGenerator.java:1961)
    at com.fasterxml.jackson.core.json.JsonGeneratorImpl._reportCantWriteValueExpectName(JsonGeneratorImpl.java:244)
    at com.fasterxml.jackson.core.json.WriterBasedJsonGenerator._verifyValueWrite(WriterBasedJsonGenerator.java:866)
    at com.fasterxml.jackson.core.json.WriterBasedJsonGenerator.writeStartObject(WriterBasedJsonGenerator.java:279)
    at hello.ItemRowSerializer.serialize(ItemRow.java:58)
    at hello.ItemRowSerializer.serialize(ItemRow.java:42)
    at com.fasterxml.jackson.databind.ser.DefaultSerializerProvider._serialize(DefaultSerializerProvider.java:480)
    at com.fasterxml.jackson.databind.ser.DefaultSerializerProvider.serializeValue(DefaultSerializerProvider.java:319)
    at com.fasterxml.jackson.databind.ObjectMapper.writeValue(ObjectMapper.java:2655)
    at com.fasterxml.jackson.core.base.GeneratorBase.writeObject(GeneratorBase.java:381)
    at hello.ItemRowSerializer.serialize(ItemRow.java:67)
    at hello.ItemRowSerializer.serialize(ItemRow.java:42)

序列化器实现

class ItemRowSerializer extends JsonSerializer<ItemRow> {

    @Override
    public void serialize(ItemRow itemRow, JsonGenerator jgen, SerializerProvider serializerProvider) throws IOException {

        String id = itemRow.getId();
        List<Object> items = itemRow.getItems();

        if (items.isEmpty()) {
            jgen.writeStartObject();
            jgen.writeFieldName(id);
            jgen.writeStartArray();
            jgen.writeEndArray();
            jgen.writeEndObject();
        }
        else {
            jgen.writeStartObject();
            Object item = items.get(0);
            jgen.writeFieldName(id);
            if (item instanceof  ItemRow){
                for (Object i : items) {
                    //ItemRow temp = (ItemRow) i;
                    //jgen.writeObjectField(temp.getId(), temp);
                    //jgen.writeObjectField(id, i);
                    jgen.writeStartObject();
                    jgen.writeObject(i);
                    jgen.writeEndObject();
                }
            }
            else {
                //jgen.writeFieldName(id);
                jgen.writeStartArray();
                for (Object arg : items) {
                    jgen.writeString(arg.toString());
                }
                jgen.writeEndArray();
            }
        }
        jgen.writeEndObject();
    }
}

Answer 1

您的序列化程序算法不正确。代码在上方。直接反序列化对象时，无需启动对象。我删除了此步骤并最小化了代码。

示例测试；

types.MergePatchType

算法；

@Test
public void serializeTest() throws JsonProcessingException
{
    ObjectMapper mapper = new ObjectMapper();

    SimpleModule module = new SimpleModule();
    module.addSerializer(ItemRow.class, new ItemRowSerializer());
    mapper.registerModule(module);

    ItemRow item1 = new ItemRow("abc", Arrays.asList("item1", "item2", "item3"));
    String result = mapper.writeValueAsString(item1);
    System.out.println(result);


    ItemRow item2 = new ItemRow("cde", Arrays.asList("item4", "item5"));


    ItemRow item6 = new ItemRow("deeper-1", Arrays.asList("item6", "item7"));
    ItemRow item7 = new ItemRow("deeper-2", Arrays.asList("item6", "item7"));
    ItemRow item8 = new ItemRow("deeper", Arrays.asList(item6, item7));

    ItemRow item3 = new ItemRow("inner-1", Arrays.asList("item6", "item7"));
    ItemRow item4 = new ItemRow("inner-2", Arrays.asList("item6", "item7"));
    ItemRow item5 = new ItemRow("inner", Arrays.asList(item3, item4, item8));




    ItemRow item = new ItemRow("combined", Arrays.asList(item1,item2,item5));
    result = mapper.writeValueAsString(item);
    System.out.println(result);

}

在Jackson中使用自定义序列化程序序列化嵌套对象时，发生JsonGenerationException

1 个答案: