Question

我有以下代码：

public interface UserRepository extends CrudRepository<User, Integer> {


@Modifying
@Transactional
@Query(value = "INSERT INTO users(email, password, name) VALUES (?,?,?)", nativeQuery = true)
void insertUserToUsers(String email, String password, String name);
}

我不想传递值，我想传递这样的用户对象：

void insertUserToUsers(User user);

Answer 1

尝试一下

public interface UserRepository extends CrudRepository<User, Integer> {


@Modifying
@Transactional
@Query(value = "INSERT INTO users(email, password, name) VALUES (:#{#user.email},:#{#user.firstname},:#{#user.name})", nativeQuery = true)
void insertUserToUsers(@Param("user") User user);
}

Answer 2

尝试此代码，

    @Modifying
@Transactional
@Query(value = "INSERT INTO users(email, password, name) VALUES (?,?,?)", nativeQuery = true)
void insertUserToUsers(String email, String password, String name);

default void insertUserToUsers(User user) {
    return insertUserToUsers(user.getEmail(), user.getPassword(), user.getName());
}

Answer 3

在使用UserRepository的地方，可以使用默认方法保存user：

例如：

@Service
public class MyService{

 @Autowired
 private UserRepository userRepository ;

 public void example(User user){

  userRepository.save(user)

 }
}

由于CrudRepository提供了一些默认方法，因此您可以检查here

Spring Boot CrudRepository查询传递对象mysql

3 个答案: