Question

我正在尝试使用curl从Java发出 POST 请求。它还有一些有效载荷。我收到状态码400。我想念什么？

以下是我在终端机中使用的卷曲。

curl --cookie "token=xyzxyzxyzxyz" --header "Content-Type:application/json" --data 
{"branchName":"name","branchId":"bid","sourceBranch":"sb","alias":"pppp","mainPackageFullPath":"main.full.path"}'
-k http://app.aws.application/api/random/create

Answer 1

您可以这样做

    String branchName="name";
    String branchId="bid";
    String sourceBranch="sb"
    String alias="ppp"

   String[] command = {"curl" "-k" "-i" "-X" POST "-H" "Content-Type: multipart/form-data" --cookie "rsession=your rsession" "Content-Type:application/json" --data{branchName+":"+branchId":"+sourceBranch":",+alias}};
    ProcessBuilder process = new ProcessBuilder(command); 
    Process p;
    try
    {
        p = process.start();
         BufferedReader reader =  new BufferedReader(new InputStreamReader(p.getInputStream()));
            StringBuilder builder = new StringBuilder();
            String line = null;
            while ( (line = reader.readLine()) != null) {
                    builder.append(line);
                    builder.append(System.getProperty("line.separator"));
            }
            String result = builder.toString();
            System.out.print(result);

    }
    catch (IOException e)
    {   System.out.print("error");
        e.printStackTrace();
    }

如何从Java运行curl命令？

1 个答案: