我有两个表“ phonebook”和“ phonecall”,我想根据callFrom和callTo在电话簿中查找姓名。
我的代码返回相同的名称,因为我仅引用callTo字段,而不能包含callFrom字段。
SELECT
phonecall.callDate,
phonecall.callTime,
phonecall.callFrom,
phonebook.personFirstname as First,
phonebook.personLastname as Last,
phonecall.callTo, phonebook.personFirstname First1,
phonebook.personLastname as Last1,
phonecall.callDuration
FROM phonecall
LEFT JOIN phonebook on
callTo = phonebook.personService
WHERE 1
ORDER BY phonecall.callDate, phonecall.callTime
此代码失败:
SELECT
phonecall.callDate,
phonecall.callTime,
phonecall.callFrom,
phonebook.personFirstname as First,
phonebook.personLastname as Last,
phonecall.callTo,
phonebook.personFirstname as First1,
phonebook.personLastname as Last1,
phonecall.callDuration
FROM phonecall
LEFT JOIN phonebook on
phonecall.callTo = phonebook.personService
LEFT JOIN phonebook on
phonecall.callFrom = phonebook.personService
WHERE 1
ORDER BY phonecall.callDate, phonecall.callTime
我知道这可能非常简单,但是我的SQL经验非常有限,还没有找到任何示例。
答案 0 :(得分:0)
这不是一个完整的解决方案,只是用来说明如何在不同的条件下两次连接同一张表,然后从每个条件返回列。
number_vector=c(1,5,26,7,94)
for (i in numbers_vector)
if ((i >24)&(i%%13 == 0)) {
print(which(numbers_vector==i))
} else {
print(0)
}