Question

为了解决问题，我有以下数据。

A = [170,170,150]
b = 160
C = [2,2]
xb = [b/(k-1) for k in C]
print(xb)

输出：

[160.0, 160.0]

现在更改C列表：

A = [170,170,150]
b = 160
C = [2,1]
xb = [b/(k-1) for k in C]
print(xb)

输出：

Error ZeroDivisionError: division by zero

好吧，预计它不会运行，现在我们找到了运行它的解决方案。

xb = []
for k in C:
    try:
        xb.append(b/(k-1))
    except ZeroDivisionError:
        xb.append(0)
print(xb)

输出：

[160.0, 0]

我的问题是如何编写上述解决方案的简短版本，例如第一个解决方案？

Answer 1

您可以检查列表推导内是否存在被零除的情况，如下所示：

<template>
  <view class="container">
    <text class="text-color-primary">My Vue Native App</text>
    </view>
</template>

<style>
.container {
  background-color: white;
  align-items: center;
  justify-content: center;
  flex: 1;
}
.text-color-primary {
  color: blue;
}
</style>

输出：

A = [170,170,150]
b = 160
C = [2,1]
xb = [b/(k-1) if k != 1 else 0 for k in C]
print(xb)

Answer 2

您的示例之一的解决方案

for (var i = 1; i < this.people.length; i++) {

Answer 3

A = [170,170,150]
b = 160
C = [2,1]
xb = [b/(k-1) if k != 1 else 0 for k in C]
print(xb)

for循环的简短版本，被零除

3 个答案: