我有一个看起来像这样的输入字符串:
url=https%3A%2F%2Fdomain.com%2Fsale-deal%3Futm_source%3Dinsider-primary-action%3Dinsider-primary-action&utm_source=FB
或
url=https%3A%2F%2Fdomain.com%2Fsale&utm_source=FB&sub_id1=M12
该字符串有时具有%3Futm_source
或非{{1}
如何获取url =和%3Futm_source%
或&utm_source
之间的链接
Regex reg = new Regex(@"url=(https%3A%2F%2Fdomain.com[a-zA-Z0-9-_/%\.]+)%3Futm_source|&utm_source");
Match result = reg.Match(inPut);
Console.WriteLine(result.Groups[1].Value));
它总是从url=
到&utm_source
答案 0 :(得分:0)
您可以使用此
(?<=url=).*?(?=%3Futm_source|&utm_source)
(?<=url=)
积极乐观。匹配url=
。.*
-匹配除换行以外的所有内容。(?=%3Futm_source|&utm_source)
-积极向前看。匹配%3Futm_source
或&utm_source