我正在尝试根据以下公式从RGB图像中获取强度值:
我的代码是:
def normalize(image): #normalize values to between 0 and 1
image -= image.min()
image /= image.max()
image = np.uint8(image * 255) #convert values to uint8 between 0-255
return image
def custom_intensity(image):
h, w, c = image.shape
intensity = np.zeros((h, w))
image = image.astype(float)
for i in range(h):
for j in range(w):
divider = image[i, j, 0] + image[i, j, 1] + image[i, j, 2]
if(divider == 0):
intensity[i, j] == 0
else:
intensity[i, j] = image[i, j, 0] * (image[i, j, 0] / divider) + \
image[i, j, 1] * (image[i, j, 1] / divider) + \
image[i, j, 2] * (image[i, j, 2] / divider)
intensity = normalize(intensity)
return intensity
效果不错,但速度较慢。我是python的新手,因此无法进一步改善。如何使此代码更高效?
答案 0 :(得分:3)
尝试一下:
image += (pow(10, -6), pow(10, -6), pow(10, -6))
intensity = (pow(image[:, :, 0], 2) + pow(image[:, :, 1], 2) + pow(image[:, :, 2], 2)) \
/ (image[:, :, 0] + image[:, :, 1] + image[:, :, 2])
答案 1 :(得分:2)
您不需要成为Python专家。
简化方程式
(R**2 + G**2 + B**2) / (R+G+B)