Question

我有一个脚本在工作，但是秒数只有一位数字。

我该如何解决2位数字的问题？示例：4：01而不是4：1

倒计时必须是5分钟

JS：

setInterval(function() {
  var d = new Date();
  var seconds = d.getMinutes() * 60 + d.getSeconds(); //convet 00:00 to seconds for easier caculation
  var fiveMin = 60 * 15; //five minutes is 300 seconds!
  var timeleft = fiveMin - seconds % fiveMin; // let's say 01:30, then current seconds is 90, 90%300 = 90, then 300-90 = 210. That's the time left
    var result = parseInt(timeleft / 60) + ':' + timeleft % 60; //formart seconds into 00:00 
  document.getElementById('test').innerHTML = result;

}, 500) //calling it every 0.5 second to do a count down

HTML：

<span id="test">6:00</span>

Answer 1

当秒数为“ x”时，您可以使用

x = x < 10 ? "0" + x : x

以适合标准数字时间格式

在这种情况下，请将其应用于脚本结尾附近的timeleft % 60。代替

var result = parseInt(timeleft / 60) + ':' + timeleft % 60;

你可以拥有

var min = parseInt(timeleft / 60);
var sec = timeleft % 60;
sec = parseInt(sec) < 10 ? "0" + sec : sec;
var result = min + ":" + sec;

Answer 2

您可以使用padStart function

  var result = parseInt(timeleft / 60) + ':' + (timeleft % 60).toString().padStart(2,'0');

setInterval(function() {
  var d = new Date();
  var seconds = d.getMinutes() * 60 + d.getSeconds(); //convet 00:00 to seconds for easier caculation
  var fiveMin = 60 * 15; //five minutes is 300 seconds!
  var timeleft = fiveMin - seconds % fiveMin; // let's say 01:30, then current seconds is 90, 90%300 = 90, then 300-90 = 210. That's the time left!
  var result = parseInt(timeleft / 60) + ':' + (timeleft % 60).toString().padStart(2,'0'); //formart seconds into 00:00 
  document.getElementById('test').innerHTML = result;

}, 500) //calling it every 0.5 second to do a count down

<span id="test">6:00</span>

倒数脚本的第二位错误

2 个答案: