在搜索了我的疑问之后,围绕着很多问题,我仍然无法获得想要的结果。 我试图将同一张表连接3次,但是Sqlserver无法识别字段。
CREATE PROCEDURE GetServices
AS
BEGIN
SELECT
[Service].ServiceID AS ServiceID,
[Service].ServiceStart AS [Data de ínicio do serviço],
EE.EntDescr AS Entidade,
EE1.PartnerID AS Parceiro,
EE2.Partner2ID AS [Segundo Parceiro],
Circuit.CircuitDescr AS [Descrição do Circuito],
Truck.TruckPlate AS Matrícula,
[Service].StartKms AS [Km's Iniciais],
[Service].StartCheck1 AS [Verificação 1],
[Service].StartCheck2 AS [Verificação 2],
[Service].StartCheck3 AS [Verificação 3],
[Service].StartCheck4 AS [Verificação 4],
[Service].StartCheck5 AS [Verificação 5],
[Service].StartCheck6 AS [Verificação 6],
[Service].ServiceEnd AS [Data de ínicio do serviço],
[Service].EndKms AS [Km's Finais],
[Service].HRCheck AS [Verificação HR],
[Service].HRNotes AS [Notas HR]
FROM
[Service]
LEFT OUTER JOIN EntEnt EE ON EE.EntID = [Service].DriverID
LEFT OUTER JOIN EntEnt EE1 ON EE1.EntID = [Service].PartnerID
LEFT OUTER JOIN EntEnt EE2 ON EE2.EntID = [Service].Partner2ID
INNER JOIN Circuit on Circuit.CircuitID = [Service].CircuitID
INNER JOIN Truck ON Truck.TruckID = [Service].TruckID
END
EE1.PartnerID AS Parceiro && EE2.Partner2ID AS [Segundo Parceiro] 收到无效的列名错误
答案 0 :(得分:0)
根据您的查询,您查询的两个字段应为ee1.EntID和EE2.entID,因为Partner1ID和Partner2ID位于服务表中
答案 1 :(得分:0)
CREATE PROCEDURE GetServices
AS
BEGIN
SELECT
[Service].ServiceID AS ServiceID,
[Service].ServiceStart AS [Data de ínicio do serviço],
EE.EntDescr AS Entidade,
Service.PartnerID AS Parceiro,
Service.Partner2ID AS [Segundo Parceiro],
Circuit.CircuitDescr AS [Descrição do Circuito],
Truck.TruckPlate AS Matrícula,
[Service].StartKms AS [Km's Iniciais],
[Service].StartCheck1 AS [Verificação 1],
[Service].StartCheck2 AS [Verificação 2],
[Service].StartCheck3 AS [Verificação 3],
[Service].StartCheck4 AS [Verificação 4],
[Service].StartCheck5 AS [Verificação 5],
[Service].StartCheck6 AS [Verificação 6],
[Service].ServiceEnd AS [Data de ínicio do serviço],
[Service].EndKms AS [Km's Finais],
[Service].HRCheck AS [Verificação HR],
[Service].HRNotes AS [Notas HR]
FROM
[Service]
LEFT OUTER JOIN EntEnt EE ON EE.EntID = [Service].DriverID
LEFT OUTER JOIN EntEnt EE1 ON EE1.EntID = [Service].PartnerID
LEFT OUTER JOIN EntEnt EE2 ON EE2.EntID = [Service].Partner2ID
INNER JOIN Circuit on Circuit.CircuitID = [Service].CircuitID
INNER JOIN Truck ON Truck.TruckID = [Service].TruckID
END
//我认为您正在使用拧表。将EE1替换为Service可能有效