Question

我有一个包含项目类别，货币，投资者数量，目标等的数据框，我想创建一个新列，该列将是“其类别的平均成功率”

   state        category main_category currency  backers country  \

0      0          Poetry    Publishing      GBP        0      GB   
1      0  Narrative Film  Film & Video      USD       15      US   
2      0  Narrative Film  Film & Video      USD        3      US   
3      0           Music         Music      USD        1      US   
4      1     Restaurants          Food      USD      224      US   

   usd_goal_real  duration  year       hour  
0        1533.95        59  2015    morning  
1       30000.00        60  2017    morning  
2       45000.00        45  2013    morning  
3        5000.00        30  2012    morning  
4       50000.00        35  2016  afternoon

我有系列格式的平均成功率

Dance           65.435209

Theater         63.796134

Comics          59.141527

Music           52.660558

Art             44.889045

Games           43.890467

Film & Video    41.790649

Design          41.594386

Publishing      34.701650

Photography     34.110847

Fashion         28.283186

Technology      23.785582

现在我想添加一个新列，其中每个列的成功率都与它们的类别匹配，即，无论行是技术，新列都将包含该行的23.78

df [category_success_rate] =我希望输出列是成功百分比，与“主类别”列中的类别匹配

Answer 1

我认为您需要GroupBy.transform配以Boolena面具df['state'].eq(1)或(df['state'] == 1)：

df['category_success_rate'] = (df['state'].eq(1)
                                 .groupby(df['main_category']).transform('mean') * 100)

替代：

df['category_success_rate'] = ((df['state'] == 1)
                                 .groupby(df['main_category']).transform('mean') * 100)

根据平均值将新列添加到数据框

1 个答案: