Question

我想匹配两个字符串中的相同单词。

代码：

nn=['berry: blueberry','blueberry and raspberry','banana vs. apple','apple is delicious']
category=['blueberry','cherry']
for s in category:
    if any(x in s for x in nn):
        first_match = list(filter(lambda x: x in s, nn))[0]
        print(first_match)

由于berry在“浆果：蓝莓”和“蓝莓与覆盆子”中，因此我想先进行匹配才能将它们都打印出来。

然后我尝试了另一种编码方式：

nn=['berry blueberry','blueberry and raspberry','banana vs. apple','apple is delicious']
#k=['benz','x5']
category=['blueberry','cherry']
for i in range(len(nn)):
    for s in category:
        if any(x in s for x in nn[i]):
            first_match = list(filter(lambda x: x in s, nn[i]))[0]
            print(first_match)

打印：

b
e
b
e
b
e
l
e

输出错误。我预期的结果是要打印：

blueberry
blueberry

Answer 1

下面是代码的一种变体，它提取了nn中的匹配值：

nn=['berry: blueberry','blueberry and raspberry',
    'banana vs. apple','apple is delicious']
category=['blueberry','cherry']
for s in category:
    matches = [x for x in nn if s in x]
    print(matches)

我认为您可以按照自己想要的方式打印输出。诀窍在于对比赛的理解。缺少的部分是如何检查是否正确。

Answer 2

您可以像这样使用in运算符：

berries = [s for s in nn if 'berry' in s]

浆果设置为['berry: blueberry', 'blueberry and raspberry']。

如果要使用类别，则可以执行以下操作：

category=['blueberry','banana']
fresh_fruit = [s for c in category for s in nn if c in s]

fresh_fruit将设置为['berry: blueberry', 'blueberry and raspberry', 'banana vs. apple']

Python：匹配列表中两个字符串中的单词

2 个答案: