我想用定界符“ /”扩展切片字符串。
例如,展开以下切片
s := []string{"5/3","9","5/4/1","6"}
应产生单个切片:
["5","9","5","6"] ["5","9","4","6"] ["5","9","1","6"]
["3","9","5","6"] ["3","9","4","6"] ["3","9","1","6"]
我几乎被困在这里
var c [][]string{}
s := []string{"5/3","9","5/4/1","6"}
for _, v := range s {
combos := strings.Split(v, "/")
for _, combo := range combos {
}
}
答案 0 :(得分:1)
除了运行时间以外,您可以通过递归来实现。
func Perm(digits [][]string) (perm [][]string) {
if len(digits) == 0 || len(digits) == 1 {
return digits
}
nextDigits := Perm(digits[1:])
for _, digit := range digits[0] {
for _, next := range nextDigits {
cat := append([]string{digit}, next...)
perm = append(perm, cat)
}
}
return perm
}