Question

我在使用PHP将数据插入到具有外键的表中时遇到问题。

我有一个名为CUSTOMER_INFORMATION的表，其字段为customer_no（PK），first_name，last_name等。）和一个CATERING_RESERVATION表，其字段为catering_no（PK），type_of_event，number_of_persons，customer_no（FK））等等......

我想在customer_no表中插入CATERING_RESERVATION但我有这个错误：

无法添加或更新子行：外键约束失败（`thesis / catering_reservation`，CONSTRAINT `catering_reservation_ibfk_1` FOREIGN KEY（`customer_no`）参考`customer_information`（`customer_no`）ON DELETE CASCADE）“

但我认为我缺少一些代码。我只是PHP的新手。真的需要帮助。

这是我的代码

<?php 
$con = mysql_connect("localhost","root","");

if(!$con){
die('could not connect:'.mysql_error());
}

mysql_select_db("thesis",$con);

//from customer information fill up form
$first_name=$_POST['first_name'];
$middle_name=$_POST['middle_name'];
$last_name = $_POST['last_name'];
$address = $_POST['address'];
$city = $_POST['city'];
$zip_code = $_POST['zip_code'];
$email_address = $_POST['email_address'];
$phone_number = $_POST['phone_number'];
$mobile_number = $_POST['mobile_number'];

$sql="INSERT INTO customer_information (first_name,middle_name,last_name,address,city,zip_code,email_address,phone_number,mobile_number) VALUES('$first_name','$middle_name','$last_name','$address','$city','$zip_code','$email_address','$phone_number','$mobile_number')";

if(!mysql_query($sql,$con)){
die('Error' .mysql_error());
}
echo " 1 record added";

//from catering infomation fill up form

$type_of_event = $_POST['type_of_event'];
$number_of_person = $_POST['number_of_person'];
$month = $_POST['month'];
$mobile_number = $_POST['day'];
$year = $_POST['year'];
$start_time = $_POST['start_time'];
$end_time = $_POST['end_time'];
$esetup_time = $_POST['esetup_time'];
$eventplace_name = $_POST['eventplace_name'];
$eventplace_address = $_POST['eventplace_address'];
$comment = $_POST['comment'];


$sql2="INSERT INTO catering_reservation (type_of_event,number_of_person,month,day,year,start_time,end_time,esetup_time,eventplace_name,eventplace_address,comment) VALUES('$type_of_event','$number_of_person','$month','$day','$year','$start_time','$end_time','$esetup_time','$eventplace_name','$eventplace_address','$comment')";

if(!mysql_query($sql2,$con)){
die('Error' .mysql_error());
}

echo " 1 record added";

?>

Answer 1

您可能没有与customer_no匹配的客户。约束要求插入的行引用实际的现有客户。确保您尝试插入的customer_no有效。

如何使用外键在表中插入数据？

1 个答案: