当光标移动时,我必须激活某些功能。因此,我在MainWidget中使用了 self.setMouseTracking(True)。但是通过这种方式, mouseMoveEvent()仅在光标下有一个空窗体时才有效。我试图在main上创建另一个小部件,但是它根本不起作用。
updateApplicationContext
该怎么办?
答案 0 :(得分:0)
如果即使在鼠标放在孩子上方时也要检测鼠标的位置,可能的选择是使用事件过滤器。
from PyQt5 import QtCore, QtGui, QtWidgets
class Widget(QtWidgets.QWidget):
def __init__(self, parent=None):
super(Widget, self).__init__(parent)
w_ = QtWidgets.QWidget()
lay_w = QtWidgets.QHBoxLayout(w_)
for c in (QtWidgets.QPushButton(), QtWidgets.QLineEdit()):
lay_w.addWidget(c)
lay = QtWidgets.QVBoxLayout(self)
for w in (QtWidgets.QPushButton(), QtWidgets.QLineEdit(), QtWidgets.QTextEdit(), w_):
lay.addWidget(w)
for ws in self.findChildren(QtWidgets.QWidget) + [self]:
ws.setMouseTracking(True)
ws.installEventFilter(self)
def eventFilter(self, obj, event):
if event.type() == QtCore.QEvent.MouseMove:
p_respect_to_window = self.mapFromGlobal(obj.mapToGlobal(event.pos()))
print(p_respect_to_window)
return super(Widget, self).eventFilter(obj, event)
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
w = Widget()
w.show()
sys.exit(app.exec_())
另一方面,如果只想在一种类型的自定义窗口小部件中执行此操作,则最好覆盖自定义窗口小部件的mouseMoveEvent方法:
from PyQt5 import QtCore, QtGui, QtWidgets
class ClickButton(QtWidgets.QPushButton):
def __init__(self, text, parent=None):
super(ClickButton, self).__init__(text=text, parent=parent)
self.setMouseTracking(True)
def mouseMoveEvent(self, event):
self.run()
super(ClickButton, self).mouseMoveEvent(event)
def run(self):
print("call to run function in button{} and time: {}".format(self.text(),
QtCore.QDateTime.currentDateTime().toString()))
class Widget(QtWidgets.QWidget):
def __init__(self, parent=None):
super(Widget, self).__init__(parent)
lay = QtWidgets.QVBoxLayout(self)
for i in range(10):
w = ClickButton(str(i), self)
lay.addWidget(w)
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
w = Widget()
w.show()
sys.exit(app.exec_())