我想从具有id + parent层次结构的CSV制作JSON树。它可以工作,但我希望输出略有不同。 而不是仅仅返回:
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我希望它返回:
'childs': { ........... }
或者只是:
'childs': { placeholder: 'Select', items: { ........... } }
这是我正在使用的代码:
'childs': { items: { ........... } }
我正在使用的data.csv是:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import csv
import re
from collections import defaultdict
from pprint import pprint
parents = defaultdict(list)
with open('data.csv',encoding="utf8") as csvfile:
reader = csv.reader(csvfile, delimiter=',', quotechar='"')
next(reader)
count = 1
for row in reader:
id_, name, admin_level, parent = row
parents[parent].append((id_, name))
count += 1
def build_tree(d, val):
return {'lc' + id_: {'val': 'lc' + id_, 'txt': name, 'childs': build_tree(d, id_)} for id_, name in d[val]}
#pprint(build_tree(parents, ''))
final = str(build_tree(parents, ''))
print(final.replace(", 'childs': {}", ""))
当前输出为:
@id,name,admin_level,parent_id
295480,Portugal,2,
2897141,Lisboa,3,295480
3920249,Aveiro,3,295480
5011694,Leiria,3,295480
5400843,Loures,4,2897141
5400844,Mafra,4,2897141
答案 0 :(得分:0)
替换'childs': build_tree(d, id_)
使用'childs' : { 'placeholder': 'Select', 'items' : build_tree(d, id_) }
或使用'childs' : { 'items' : build_tree(d, id_) }
此外,您要替换掉空的子键print(final.replace(", 'childs': {}", ""))
也是不好的。
{'val': 'lc' + id_, 'txt': name, 'childs': build_tree(d, id_)}
是这样建造的:
obj = {'val': 'lc' + id_, 'txt': name}
childs = build_tree(d, id_)
if childs:
obj['childs'] = childs
build_tree
如下所示:
def build_tree(d, val):
d = {}
for id_, name in d[val]:
obj = {'val': 'lc' + id_, 'txt': name}
childs = build_tree(d, id_)
if childs:
obj['childs'] = childs
d['lc' + id_] = obj
return d