Question

我正在尝试制作一个简单的井字游戏。我已经写了确定谁获胜的逻辑，并且文本字段显示了获胜者。一旦有人中奖，我就会显示一个重置按钮。并且我已将按钮的onclick属性设置为执行此操作的功能重置

public void reset(View view){
        for(int i=0;i<playerAt.length;i++)
            playerAt[i]=2;
        activeGame=1;
        activePlayer=1;

        Button but = (Button) findViewById(R.id.button);
        TextView text = (TextView) findViewById(R.id.text);

        but.setVisibility(View.INVISIBLE);
        text.setVisibility(View.INVISIBLE);

        GridLayout grid = (GridLayout) findViewById(R.id.grid);

        for(int i=0;i<grid.getChildCount();i++){
            ImageView block = (ImageView) grid.getChildAt(i);
            block.setImageDrawable(null);
        }

    }

我已经研究了仅在该站点上循环访问网格对象的方法，但似乎无效。我按下按钮后，应用程序将在模拟器中关闭。如果我删除了循环，而是运行了一个简单的循环，如

for(int i=0;i<9;i++)

然后它可以正常工作，但是显然，它什么也不会做。基本上，我希望我的“重置”按钮清除网格布局中的所有条目。我有他们要清除的黑点和红点的图像。

但是这种方式我无法做到。

我也尝试了不使用循环

ImageView block = (ImageView) grid.getChildAt(0);
block.setImageDrawable(null);

但是还是同样的结果：按下按钮后，应用会立即关闭。可能这不是最新的android studio版本中的方式如果您想在MainActivity.java文件中查看我的完整代码，则为

package com.example.nik7.tictactoe;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.GridLayout;
import android.widget.ImageView;
import android.widget.TextView;

import java.nio.InvalidMarkException;

public class MainActivity extends AppCompatActivity {

    int activePlayer = 1;
    int activeGame = 1;
    int [][]winningP = {{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};
    int []playerAt = {2,2,2,2,2,2,2,2,2};

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }

    public void drop(View view){
        ImageView block = (ImageView) view;
        int currentPosition = Integer.parseInt(block.getTag().toString());

        if(activeGame==0)
            return;

        if(playerAt[currentPosition]==1 || playerAt[currentPosition]==0)
            return;

        playerAt[currentPosition] = activePlayer;

        if(activePlayer==1) {
            block.setImageResource(R.drawable.black);
            activePlayer = 0;
        }

        else{
            block.setImageResource(R.drawable.red);
            activePlayer=1;
        }


        //check if someone has won
        for(int[] wp:winningP){
            if(playerAt[wp[0]] == playerAt[wp[1]] && playerAt[wp[1]] == playerAt[wp[2]] && playerAt[wp[0]] != 2){
                activeGame=0;
                Button but = (Button) findViewById(R.id.button);
                TextView text = (TextView) findViewById(R.id.text);

                but.setVisibility(View.VISIBLE);
                text.setVisibility(View.VISIBLE);
                text.setText((activePlayer==1)?"red has won":"black has won");
            }
        }
    }

    public void reset(View view){
        for(int i=0;i<playerAt.length;i++)
            playerAt[i]=2;
        activeGame=1;
        activePlayer=1;

        Button but = (Button) findViewById(R.id.button);
        TextView text = (TextView) findViewById(R.id.text);

        but.setVisibility(View.INVISIBLE);
        text.setVisibility(View.INVISIBLE);

        GridLayout grid = (GridLayout) findViewById(R.id.grid);

        ImageView block = (ImageView) grid.getChildAt(0);
        block.setImageDrawable(null);


    }











}

Answer 1

尝试导入

import androidx.gridlayout.widget.GridLayout;

代替

import android.widget.GridLayout;

遍历网格元素

1 个答案: