Question

我在mongoDB中有一条记录，如下所示。需要查询以使用startTime获得前一天的结果。

{
    "_id": ObjectId("5c08d195d38e4040788c789a"),
    "jobName": "test-ci-build",
    "build": "474",
    "buildURL": "https://example.com/test-ci-build/474/",
    "result": "SUCCESS",
    "startTime": "2018-12-06T05:42:22+0000",
    "duration": "1 hr 54 min",
    "startTimeInMillis": 1544074942061,
    "triggeredBy": "Started by timer",
    "commit": "b8a04837f1c285e6d9d8852af5801419acd047cb",
    "date": ISODate("2018-12-06T07:36:53.045Z")
}

Answer 1

在startTime字段上使用$lt或$lte MongoDB运算符，您可以获得所需的数据。

您可以使用：

db.collection.find({startTime:{$lte: "2018-12-06T05:42:22+0000"}})

或

db.collection.find({startTime:{$lte: ISODate("2018-12-06T05:42:22+0000")}})

考虑为您的“ startDate

db.collection.aggregate([
  {
    $addFields: {
      yesterdays_date: {
        $subtract: [
          new Date().getTime(),
          86400000
        ]
      }
    }
  },
  {
    $addFields: {
      convertedDate: {
        $toDate: "$yesterdays_date"
      }
    }
  },
  {
    $addFields: {
      "dateComp": {
        "$cmp": [
          "$date",
          "$convertedDate"
        ]
      }
    }
  },
  {
    $match: {
      "dateComp": -1
    }
  },
  {
    $project: {
      yesterdays_date: 0,
      convertedDate: 0,
      dateComp: 0
    }
  }
])

我在mongoDB中有一条记录，如下所示。需要查询以使用startTime获得前一天的结果

1 个答案: