Question

我尝试通过以下方式运行查询：

        SELECT 
            `doctors`.*,
            (
                SELECT GROUP_CONCAT(`areas`.`areaName` SEPARATOR ', ')
                FROM `areas_has_doctors`
                INNER JOIN `areas` ON `areas`.`areaId` = `areas_has_doctors`.`areaId`
                WHERE `areas_has_doctors`.`doctorId` = `doctors`.`doctorId`
            ) as `areas`,
            (
                SELECT GROUP_CONCAT(`areas`.`areaId`)
                FROM `areas_has_doctors`
                INNER JOIN `areas` ON `areas`.`areaId` = `areas_has_doctors`.`areaId`
                WHERE `areas_has_doctors`.`doctorId` = `doctors`.`doctorId`
            ) as `areasIdies`
        FROM 
            `cats_has_doctors`
            INNER JOIN `doctors` ON `doctors`.`doctorId` = `cats_has_doctors`.`doctorId` 
        WHERE 
            `cats_has_doctors`.`catId` = '1' && `doctors`.`disable` = 0
        GROUP BY 
            `cats_has_doctors`.`relationId`
         HAVING FIND_IN_SET('1,2,3,4', `areasIdies`)

具有10.0.21-MariaDB - MariaDB服务器的服务器但是在服务器上：

5.5.61-cll - MySQL Community Server (GPL)

我得到了错误：

Unknown column 'areasIdies' in 'having clause'

我该怎么办？

Answer 1

也许它认为areaIdies是变量？

我会尝试将areaIdies子查询拉入临时表并进行尝试。只需保留查询即可进行测试，但只需在顶部进行并更改set参数中的查找即可。

CREATE TEMPORARY TABLE IF NOT EXISTS areasIdiesTemp AS (
    SELECT GROUP_CONCAT(`areas`.`areaId`)
    FROM `areas_has_doctors`
    INNER JOIN `areas` 
    ON `areas`.`areaId` = `areas_has_doctors`.`areaId`
    WHERE `areas_has_doctors`.`doctorId` = `doctors`.`doctorId`
);

SELECT 
    `doctors`.*,
    (
        SELECT GROUP_CONCAT(`areas`.`areaName` SEPARATOR ', ')
        FROM `areas_has_doctors`
        INNER JOIN `areas` ON `areas`.`areaId` = `areas_has_doctors`.`areaId`
        WHERE `areas_has_doctors`.`doctorId` = `doctors`.`doctorId`
    ) as `areas`,
    (
        SELECT GROUP_CONCAT(`areas`.`areaId`)
        FROM `areas_has_doctors`
        INNER JOIN `areas` ON `areas`.`areaId` = `areas_has_doctors`.`areaId`
        WHERE `areas_has_doctors`.`doctorId` = `doctors`.`doctorId`
    ) as `areasIdies`
FROM 
    `cats_has_doctors`
    INNER JOIN `doctors` ON `doctors`.`doctorId` = `cats_has_doctors`.`doctorId` 
WHERE 
    `cats_has_doctors`.`catId` = '1' && `doctors`.`disable` = 0
GROUP BY 
    `cats_has_doctors`.`relationId`
HAVING FIND_IN_SET('1,2,3,4', `areasIdiesTemp`);

MySQL 5.5中“具有子句”中的未知列

1 个答案: