Question

我是Python的新手，并不擅长Python。我正在尝试从名为Transfermarkt的网站（我是足球迷）进行网络抓取，但是当我尝试提取数据时，它给了我HTTP错误404。这是我的代码：

from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup

my_url = "https://www.transfermarkt.com/chelsea-fc/leihspielerhistorie/verein/631/plus/1?saison_id=2018&leihe=ist"




uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()

page_soup = soup(page_html, "html.parser")


for che in chelsea:
          player = che.tbody.tr.td.table.tbody.tr.td["spielprofil_tooltip tooltipstered"]



print("player: " +player)

错误提示：

Traceback (most recent call last):
  File "C:\Users\x15476582\Desktop\WebScrape.py", line 12, in <module>
    uClient = uReq(my_url)
  File "C:\Python36-32\lib\urllib\request.py", line 223, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Python36-32\lib\urllib\request.py", line 532, in open
    response = meth(req, response)
  File "C:\Python36-32\lib\urllib\request.py", line 642, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python36-32\lib\urllib\request.py", line 570, in error
    return self._call_chain(*args)
  File "C:\Python36-32\lib\urllib\request.py", line 504, in _call_chain
    result = func(*args)
  File "C:\Python36-32\lib\urllib\request.py", line 650, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 404: Not Found

非常感谢任何帮助，谢谢大家x

Answer 1

如上所述，Rup表示您的用户代理可能已被服务器拒绝。

尝试使用以下内容扩展代码：

import urllib.request  # we are going to need to generate a Request object
from bs4 import BeautifulSoup as soup

my_url = "https://www.transfermarkt.com/chelsea-fc/leihspielerhistorie/verein/631/plus/1?saison_id=2018&leihe=ist"

# here we define the headers for the request
headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.13; rv:63.0) Gecko/20100101 Firefox/63.0'}

# this request object will integrate your URL and the headers defined above
req = urllib.request.Request(url=my_url, headers=headers)

# calling urlopen this way will automatically handle closing the request
with urllib.request.urlopen(req) as response:
    page_html = response.read()

上面的代码之后，您可以继续进行分析。 Python文档中有一些关于此主题的有用页面：

https://docs.python.org/3/library/urllib.request.html#examples

https://docs.python.org/3/library/urllib.request.html

Mozilla的文档包含大量用户代理字符串，供您尝试：

https://developer.mozilla.org/en-US/docs/Web/HTTP/Headers/User-Agent

使用Python的Web爬网给出HTTP错误404：找不到

1 个答案: