Question

我的目标是获取介于start和stop之间的所有数字。如果起点超过定义的最大值（restart_point），则应该再次从1开始

例如：

start = 4
stop = 8
restart_point = 12

结果应为：[4, 5, 6, 7, 8]

start = 9
stop = 3
restart_point = 12

结果应为：[9, 10, 11, 12, 1, 2, 3]

以下代码有效，但我发现它有点复杂。我会为替代解决方案感到高兴。

start = 10
stop = 3
restart_point = 12

if stop - start < 0:
  difference = restart_point - start + stop
else:
  difference = stop - start

numbers = []

r = 0
for i in range(difference + 1):
  val = i + start
  if val > restart_point:
    r += 1
    val = r
  numbers.append(val)

print(numbers)
# result -> [10, 11, 12, 1, 2, 3]

Answer 1

从您的简单示例中可以看出，我可以假设stop和start都在1到restart_point之间（含）。这样就足够简单了：

start, stop, restart_point = 10, 3, 12

if stop < start:
    stop += restart_point

numbers = []
for i in range(start-1, stop):
    val = i % restart_point + 1

    numbers.append(val)

print(numbers)

输出：

[10, 11, 12, 1, 2, 3]

Answer 2

如果需要循环输入，请记住使用mod：

start = 9
stop = 3
restart_point = 12

while start % restart_point != stop:
    print(start % restart_point)
    start = start + 1

基于0索引，但很容易将其修改为基于1索引。留给你：）

Answer 3

[i for i in range(start, stop+1)] if start<stop else [i for i in range(start, restart_point+1)] + [i for i in range(1, stop+1)]

Answer 4

我想我会做这样的事情：

numbers = []
x = start

while x <= stop:
    if x > restart_point:
        x = 1
    numbers.append(x)
    x = x + 1

Answer 5

start = 9
stop = 3
restart_point = 12
l = []
if restart_point > stop:
    l = l + [i for i in range(start,restart_point)] + [i for i in range(1, stop+1)]
else:
    l = l + [i for i in range(start, stop+1)]

print(l)

输出：

(python37) C:\Users\Documents>py test.py
[9, 10, 11, 1, 2, 3]

Answer 6

这里是：

start, stop, restart_point = (10, 3, 12)
x = list(range(start, 1 + min(stop, restart_point))) + \
    list(range(start, 1 + (start>stop) * max(stop, restart_point))) + \
    list(range(1, 1 + (start>stop) *stop))
print(x)

输出

[10, 11, 12, 1, 2, 3]

如果超过最大值，则获取启动，停止和重启计数器之间的数字

6 个答案: