与您的代码有关：

Question

我在jupyter笔记本中没有获得以下代码的输出。此代码基本上检查单词的平均长度并将其打印出来。我发现在将每个单词附加到“新”（列表）之后，while循环甚至无法正常工作。

我知道还有其他方法可以以更简单的方式执行此操作，但是我希望它可以正常工作。

st = 'Print every word in this sentence that has an even number of letters'
new=[]
i=0
for words in st.split():
    new.append(words)
l=len(st)
while i<=l:
    if len(new[i])%2==0:
        print(new[i])
        i=i+1

Answer 1

有几个问题。例如，l = len(st)应该是l = len(new)，i <= l应该是i < l，并且i=i+1应该被分隔。

另一方面，更好的方法是

st = "Print every word in this sentence that has an even number of letters"
for word in st.split():
    if len(word) % 2 == 0:
        print(word)

Answer 2

我不知道如何解决您的代码，因为它有太多错误。刚刚写了最接近可能的解决方案

docker pull

Answer 3

问题是i=i+1发生在if语句中。这意味着我从不超过0，因为第一个单词的长度是奇数。要解决此问题，请将i = i + 1放在if语句之外。

while i<=l:
    if len(new[i])%2==0:
        print(new[i])
    i=i+1

Answer 4

由于第一个条件不满足并且i不会增加，因此您会收到无限循环。

Answer 5

与您的代码有关：

st = 'Print every word in this sentence that has an even number of letters'
new=[] # You can create the list of words here instead of a loop
i=0
for words in st.split():
    new.append(words)
l=len(st)    # len(new)
while i<=l:  # i < l (since indexing of i starts from 0 to n-1 length
    if len(new[i])%2==0:
        print(new[i])
        i=i+1 # this needs to be outside loop, since it will only increment if even word is found

更新代码：

st = 'Print every word in this sentence that has an even number of letters'
new = s st.split()
i = 0
l = len(new)
while i < l:
    if len(new[i])%2 == 0:
        print (new[i])
    #else:
    #    pass
    i = i+1

Answer 6

st = "Print every word in this sentence that has an even number of letters"
new=[]
i=0
for words in st.split():
    new.append(words)
l=len(words)
while i<l:
    if len(new[i])%2==0:
        print(new[i])
    i=i+1

此外，您可以使用以下命令执行相同的任务：

st="Print every word in this sentence that has an even number of letters"
[word for word in st.split() if len(word)%2==0]

为什么我没有得到以下代码的输出？

6 个答案:

与您的代码有关：

更新代码：