尝试从特定于数据库GridView的用户进行更新(OleDbCommand)

时间:2018-12-02 04:56:47

标签: c# asp.net database oledb oledbcommand

嗨,我正在为用户GridView数据库升级而努力,我的更新行有问题,当我单击更新时它告诉我,行已更新成功,但实际上并没有更新:(

代码:

1 Asp.net(OleDB)

 protected void AdminBook_RowUpdating(object sender, GridViewUpdateEventArgs e)
{
    try
    {
        using (OleDbConnection sqlCon = new OleDbConnection(connectionStr))
        {
            sqlCon.Open();
            string query = "UPDATE Users SET FirstName=@FirstName,LastName=@LastName,UserPass=@UserPass,Gender=@Gender,Birthday=@Birthday,Email=@Email WHERE UserID=@id";
            OleDbCommand sqlCmd = new OleDbCommand(query, sqlCon);
            sqlCmd.Parameters.AddWithValue("@FirstName", (AdminBook.Rows[e.RowIndex].FindControl("txtFirstName") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@LastName", (AdminBook.Rows[e.RowIndex].FindControl("txtLastName") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@UserPass", (AdminBook.Rows[e.RowIndex].FindControl("txtUserPass") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@Gender", (AdminBook.Rows[e.RowIndex].FindControl("txtGender") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@Birthday", (AdminBook.Rows[e.RowIndex].FindControl("txtBirthday") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@Email", (AdminBook.Rows[e.RowIndex].FindControl("txtEmail") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@UserName", (AdminBook.Rows[e.RowIndex].FindControl("txtUserName") as TextBox).Text.Trim());
            sqlCmd.Parameters.AddWithValue("@id", Convert.ToInt32(AdminBook.DataKeys[e.RowIndex].Value.ToString()));
            sqlCmd.ExecuteNonQuery();
            AdminBook.EditIndex = -1;
            PopulateGridView();
            lblSuccessMessage.Text = "עריכת הנתונים התבצעה בהצלחה";
            lblErrorMessage.Text = "";
        }
    }
    catch (Exception ex)
    {
        lblSuccessMessage.Text = "";
        lblErrorMessage.Text = ex.Message;
    }
}

2 HTML(非常简短)

    <asp:GridView ID="AdminBook" runat="server" AutoGenerateColumns="False" 
      ShowFooter="True" DataKeyNames="UserID"
            ShowHeaderWhenEmpty="True"

            OnRowCommand="AdminBook_RowCommand" OnRowEditing="AdminBook_RowEditing" OnRowCancelingEdit="AdminBook_RowCancelingEdit"
            OnRowUpdating="AdminBook_RowUpdating" OnRowDeleting="AdminBook_RowDeleting"

            BackColor="White" BorderColor="#999999" BorderStyle="Solid" 
      BorderWidth="1px" CellPadding="3" ForeColor="Black" GridLines="Vertical">

您可以看到的图片: Here you can see that it show the success message

请帮助我...因为它成功但在数据库中并未真正更新:(

1 个答案:

答案 0 :(得分:0)

查询的主要问题是此参数定义的存在:

sqlCmd.Parameters.AddWithValue("@UserName", (AdminBook.Rows[e.RowIndex].FindControl("txtUserName") as TextBox).Text.Trim());

在查询字符串中不存在,它具有7个参数,而不是cmd.Parameters.Add()定义的8个参数:

UPDATE Users SET FirstName=@FirstName,LastName=@LastName,UserPass=@UserPass,Gender=@Gender,Birthday=@Birthday,Email=@Email WHERE UserID=@id

请注意,OLE DB无法识别命名参数,它只能识别positional parameters(查询参数将按照其定义顺序进行处理)。使用代码中的当前顺序,UserName参数可能被错误地分配为id,并且由于提供的值与UserID列中存储的任何值都不匹配,因此不会更新任何数据。 / p>

因此,您应该删除上面提到的行,以便查询参数与其在查询字符串中出现的顺序完全匹配:

string query = "UPDATE Users SET FirstName=@FirstName,LastName=@LastName,UserPass=@UserPass,Gender=@Gender,Birthday=@Birthday,Email=@Email WHERE UserID=@id";

OleDbCommand sqlCmd = new OleDbCommand(query, sqlCon);

sqlCmd.Parameters.AddWithValue("@FirstName", (AdminBook.Rows[e.RowIndex].FindControl("txtFirstName") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@LastName", (AdminBook.Rows[e.RowIndex].FindControl("txtLastName") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@UserPass", (AdminBook.Rows[e.RowIndex].FindControl("txtUserPass") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@Gender", (AdminBook.Rows[e.RowIndex].FindControl("txtGender") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@Birthday", (AdminBook.Rows[e.RowIndex].FindControl("txtBirthday") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@Email", (AdminBook.Rows[e.RowIndex].FindControl("txtEmail") as TextBox).Text.Trim());
sqlCmd.Parameters.AddWithValue("@id", Convert.ToInt32(AdminBook.DataKeys[e.RowIndex].Value.ToString()));

或在UserName子句之前添加WHERE列,而无需更改参数顺序:

string query = "UPDATE Users SET FirstName=@FirstName,LastName=@LastName,UserPass=@UserPass,Gender=@Gender,Birthday=@Birthday,Email=@Email,
                UserName=@UserName WHERE UserID=@id";