Question

我正试着用触摸拖动以simetric曲线的方式移动精灵位置。到目前为止，我使用以下代码没有运气

-(BOOL) ccTouchBegan:(UITouch*)touch withEvent:(UIEvent *)event
{
lastTouchLocation = [MultiLayer locationFromTouch:touch];   
return YES;
}

-(void) ccTouchMoved:(UITouch*)touch withEvent:(UIEvent *)event
{
CGPoint currentTouchLocation = [MultiLayer locationFromTouch:touch];
moveTo = ccpSub(lastTouchLocation, currentTouchLocation);
lastTouchLocation = currentTouchLocation;
} 

-(void) update:(ccTime)delta 
{       
CCSprite* sprite = [sprites objectAtIndex:1];
if (moveTo.x != 0){
    float X = sprite.position.x + moveTo.x;
    float Y =  sprite.position.y + (pow(X,2));
    sprite.position = CGPointMake(X, Y);
}
}

我试图模拟的曲线方式是y = x ^ 2。这是真的吗？提前谢谢！

Answer 1

是的，这是可能的。您可以在尝试时手动执行此操作，但最好使用内置解决方案。在cocos2d引擎中有一个CCJumpTo和CCJumpBy动作。它们是为抛物线移动而创建的。使用它们

曲线精灵运动COCOS2D

1 个答案: