我有这个df:
library(dplyr)
x <- c("aa1","aa1","bb1","bb1","cc1","cc1")
y <- c(1,2,1,2,1,2)
df <- data.frame(y,x)
它看起来像这样:
y x
1 1 aa1
2 2 aa1
3 1 bb1
4 2 bb1
5 1 cc1
6 2 cc1
我如何使用dplyr包(突变)评估下面的行是否具有与我想要的结果相同的值:
y x z
1 1 aa1 TRUE #Comparing from column x the 1st entry vs the 2nd one
2 2 aa1 FALSE #Comparing from column x the 2nd entry vs the 3rd one
3 1 bb1 TRUE #Comparing from column x the 3rd entry vs the 4th one
4 2 bb1 FALSE #...
5 1 cc1 TRUE #...
6 2 cc1 FALSE #...
答案 0 :(得分:0)
您要寻找的功能是线索:
mutate(df, z=x==lead(x))
相反,顺便说一句是lag()
为什么要知道呢,顺便说一句?我怀疑您要实现的目标是group_by()
答案 1 :(得分:0)
您甚至可以将base R与
duplicated(df$x, fromLast = TRUE)